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4 years ago

Whats 1+1=? hi how are you? I already know the answer I just wanted ya'll to have some points.

Mathematics

2 answers:

eimsori [14]4 years ago

4 0

The answer is two. Thanks for the points stranger! ❤️

d1i1m1o1n [39]4 years ago

3 0

Its 2 and thanks for the points

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15 - (-8) answer if you could please and thank you

RSB [31]

Hi there!

»»————-　★　————-««

I believe your answer is:

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Calculating the answer...}}\\\\15-(-8)\\-----------\\\rightarrow 15-1(-8)\\\\\rightarrow 15 + 8 \\\\\rightarrow \boxed{23}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

5 0

3 years ago

Please help due today

amid [387]

Answer:

asdadsad

Step-by-step explanation:asdsadadasd

3 0

3 years ago

A system of identifying call letters uses call letters that begin either with E or W. Some have a total of 2 letters, and others

Klio2033 [76]

Answer:

If repetition is allowed then the different call letters possible are 1404.

If repetition is allowed then the different call letters possible are 1250.

Step-by-step explanation:

The call letter are of either 2 letter or 3 letters.

And for them to be identified they should start with either E or W.

If Repetition is allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : E _

The second place can be filled any of the 26 letters.

Possible number of call letters starting with W : W _

The second place can be filled any of the 26 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : E _ _

The second place and third place can be filled with any of the 26 letters.

Possible number of call letters starting with W : W _ _

The second place and third place can be filled with any of the 26 letters.

Total number of possible letters: 26 + 26 + (26)² + (26)² = 1404

Thus, if repetition is allowed then the different call letters possible are 1404.

If Repetition is not allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : E _

The second place can be filled any of the 25 letters.

Possible number of call letters starting with W : W _

The second place can be filled any of the 25 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : E _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Possible number of call letters starting with W : W _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Total number of possible letters: 25 + 25+ (25 × 24) + (26 × 24) = 1250

Thus, if repetition is allowed then the different call letters possible are 1250.

5 0

3 years ago

N is the set of all positive multiples of 3, and W s the set of all squares of integers. Which of the following numbers belongs

Crazy boy [7]

36 because 3 x 12 = 36 and $6^{2}$ = 36

7 0

3 years ago

A. Find PR in the diagram b. Find the perimeter of quadrilateral PQRS

Elan Coil [88]

Answer:

Step-by-step explanation:

The quadrilateral has 4 sides and only two of them are equal.

A) to find PR, we will consider the triangle, PRQ.

Using cosine rule

a^2 = b^2 + c^2 - 2abcos A

We are looking for PR

PR^2 = 8^2 + 7^2 - 2 ×8 × 7Cos70

PR^2 = 64 + 49 - 112 × 0.3420

PR^2 = 113 - 38.304 = 74.696

PR = √74.696 = 8.64

B) to find the perimeter of PQRS, we will consider the triangle, RSP. It is an isosceles triangle. Therefore, two sides and two base angles are equal. To determine the length of SP,

We will use the sine rule because only one side,PR is known

For sine rule,

a/sinA = b/sinB

SP/ sin 35 = 8.64/sin110

Cross multiplying

SPsin110 = 8.64sin35

SP = 8.64sin35/sin110

SP = (8.64 × 0.5736)/0.9397

SP = 5.27

SR = SP = 5.27

The perimeter of the quadrilateral PQRS is the sum of the sides. The perimeter = 8 + 7 + 5.27 + 5.27 = 25.54 cm

6 0

3 years ago