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goblinko [34]
3 years ago
9

Please help due today

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

asdadsad

Step-by-step explanation:asdsadadasd

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Converting ounces to pounds
Bond [772]
There are 16 ounces in 1 pound.
8 0
3 years ago
A sample of students from an introductory psychology class were polled regarding the number of hours they spent studying for the
Anni [7]

Answer:

8.68,13.16

Step-by-step explanation:

Hint- First we have to calculate the mean and standard deviation of the sample and then applying formula for confidence interval we can get the values.

Mean of the sample is,

\mu=\dfrac{\sum _{i=1}^{24}a_i}{24}=\dfrac{262}{24}=10.92

Standard deviation of the sample is,

\sigma =\sqrt{\dfrac{\sum _{i=1}^{24}\left(x_i-10.92\right)^2}{24-1}}=5.6

The confidence interval will be,

=\mu \pm Z\dfrac{\sigma}{\sqrt{n}}

Here,

Z for 95% confidence interval is 1.96, and n is sample size which is 24.

Putting the values,

=10.92 \pm 1.96\cdot \dfrac{5.6}{\sqrt{24}}

=10.92 \pm 2.24

=8.68,13.16

Confidence interval is used to express the degree of uncertainty associated with a sample.

95% confidence interval means that if we used the same sampling method to select different samples and calculate an interval, we would expect the true population parameter to fall within the interval for 95% of the time.

5 0
3 years ago
Triangle ABC has vertices A0,0), B(3,2)and C(0,4). The triangle may be classified as
lawyer [7]

Answer:

aceite triangle

Step-by-step explanation:

because when you put it in a graph all ángles are acitr

5 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
4.6w - 3 + 6.4x - 1.9y
torisob [31]

Answer:

What do you want me to do? Its already simplified to its lowest terms

7 0
2 years ago
Read 2 more answers
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