Start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm
now, write the question as a system of equations
3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300
now you have a system of equations
3x+2y =200
4x+4y =300
solve for x and y
Answer:
0.1111
Step-by-step explanation:
Given that you roll two dice.
the average of the high and low roll is exactly 3,
Since die can show only 1 to 6 we can say average can be 3 in each of the following case.
(1,5) (2,4) (3,3) (4,2) (5,1)
There cannot be any other combination to get average of 3.
Thus favourable events = 4
Sample space will have
(1,1)...(1,6)
(2,1)....
(6,1)...(6,6) i.e. 36
So probability that the average of the high and low roll is exactly 3
=
The square root of 7 would like between 2 and 3. This is because 2 x 2 is 4's square root and 3 x 3 is nine's square root. Seven is between four and nine.
i think that it is the third one
Answer: 
Step-by-step explanation:
Here the total numbers are 1, 4, 3, 7, 6
Since the total number of possible arrangement =
The total number of the odd numbers in the given numbers = 3
Thus the possible arrangement that the first three digits will be odd numbers = 
Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement =
= 