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Ganezh [65]
3 years ago
5

Solve each system by elimination.

Mathematics
2 answers:
Vikki [24]3 years ago
5 0
X=6/3=2 is the correct answer 3x-4y=-2
Lerok [7]3 years ago
3 0
X=6/3=2 is the answer
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The vertices of a trapezoid are shown below. P(0, 0), Q(2, 0), R(2, 7), S(0, 14) This trapezoid is dilated about the origin by a
dimulka [17.4K]
So, point S seems to be the top left corner of a 4 sided trapezoid. If you graph this then it may be easier to imagine. Dilate means to get bigger, if you have trouble remembering this, think about how the pupil dilates when you’re in a dark room. (It gets bigger). So this shape is dilated about the origin which means that points that have 0’s in them now (for example (0,0) or (5,0) ) are only going to change for the number that isn’t a 0. So (0,0) dilated by any factor is still (0,0). But if a point was at (0,5) and dilated by a factor of 2, the new point would be (0,10). This is only the case if the shape is dilated around the origin. (Origin is at point (0,0) ). So point S we can see (0,14) has a 0 in it so we are only multiplying the 14 by the scale factor of 5. So 14 * 5 is 70. So the new location of S’ would be (0,70)
7 0
3 years ago
30 = y - 2<br> and work plzzz
9966 [12]

Answer:

Step-by-step explanation:

y - 2 = 30

y = 32

3 0
3 years ago
Read 2 more answers
5/3x-4/3x-1=8 solve please
SOVA2 [1]

Answer:x=27

Step-by-step explanation:

3 0
2 years ago
What is the correct equation of the circle with the center (4, 6) and radius 6?
jasenka [17]

I know it's either A B C or D.

6 0
3 years ago
Graph the exponential function<img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%5E%7Bx%7D%20%20" id="TexForm
tatyana61 [14]

f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

3 0
3 years ago
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