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3 years ago

15 Points and I mark Brainliest.

Mathematics

1 answer:

kramer3 years ago

3 0

Answer:

the answer is H

Step-by-step explanation:

plug X into each equation to find Y

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Help with problems 5 & 6 please.

ASHA 777 [7]

Both problems can be solved similarly since both shapes are Quadrilateral hence the sum of thier interior angels is 360
5.)
(x)+(x)+(4x-26)+(2x+18)=360
8x-8=360
x-1=45
x=46
6.)
(2x)+(x)+(x+10)+(2x-16)=360
6x-6=360
x-1=60
x=61

6 0

3 years ago

Here is Priya's calculation of 906 divided by 3

dmitriy555 [2]

Answer:

Her mistake is that she wrote a two in the tenths place and zero in the ones place.

Step-by-step explanation:

3 can't go into zero so she had to write a zero in the tenths place. And 3 can go into 6 two times so she must write a 2 in the ones place.

Hope this Helps :)

Plz make me brainliest

3 0

3 years ago

Solve for x: one over four (4x + 15) = 24 (5 points)

skelet666 [1.2K]

The answer is eighty one over four

4 0

4 years ago

WILL MARK BRAINLIEST. When ∆RST is translated 4 units down, what are the apparent coordinates of T’?

jolli1 [7]

Answer:

T' is at (-1,-8)

Step-by-step explanation:

When we translate down 4 units, we will subtract 4 from the y coordinate

T is at (-1,-4)

We need to subtract 4 from the y coordinate

T' is at (-1,-4-4)

T' is at (-1,-8)

5 0

3 years ago

Read 2 more answers

Operations with rational expressions

Scorpion4ik [409]

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}$

Solution:

Given expression:

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}$

To solve the given expression:

First simplify: $\frac{50-2 w^{2}}{3 w^{2}+9 w-30}$

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}$

Cancel the common factor (w + 5).

$$=-\frac{2(w-5)}{3(w-2)}$

Now substitute this in the given expression.

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}$

Multiply the fractions $\frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}$

$$=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}$

Factor the denominator $3(w-2)(6 w-30) =18(w-2)(w-5)$

$$=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}$

Cancel the common factor 2(w – 5).

$$=-\frac{w^{2}+5 w-14}{9(w-2)}$

Factor the numerator $w^{2}+5 w-14=(w-2)(w+7)$

$$=-\frac{(w-2)(w+7)}{9(w-2)}$

Cancel the common factor (w – 2).

$$=-\frac{w+7}{9}$

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}$

3 0

3 years ago