Answer:
H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.
Ha: At least one of the proportions in the null hypothesis is false.
Step-by-step explanation:
On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:
H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.
Ha: At least one of the proportions in the null hypothesis is false.
And in order to test it we need to have observed and expected values. On this case we can calculate the Expected values like this



The observed values are not provided. The statistic on this case is given by:

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.
We can calculate the p valu like this:

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.
Hi, Sthefy! This is just a little bit of adding, not too hard! Okay, 5 tens. What is 1 ten equal to? 10!
2 tens? 20!
3 tens? 30!
You get the idea? Okay, so now we know that 5 tens are 50. Now, ones. All we need to do now is add 13 + 50! Let's break it down, make it easier.
13.. Hm, what can we do to make this easier?
Ah! Take away the 3 from 13 for now. So just 10 + 50. That's 60. Now, add the 3. 63! That wasn't hard, was it? I hope I helped you!
Answer:
bad⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Answer:
Option d
Step-by-step explanation:
Given that television networks frequently run public opinion polls on issues of concern. One network conducted a scientific poll asking a question concerning the approval rating of the way President Obama was handling the Iraq War. At about the same time a second network ran an online poll using a very similar question.
Observed data is
Poll Scien Online total
approve 339 385 724
disapprove 780 573 1363
1119 958 2087

(Two tailed chi square test)
Let us find out expected and chi square
Expected = row total x column total/grand total
The cell count expected in the online poll for those who approve
=
chi square = 7.81
Hence option d is right.