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3 years ago

Make Sense and Persevere What do you know? Whatare you trying to find?

Mathematics

1 answer:

marysya [2.9K]3 years ago

3 0

Answer:

Step-by-step explanation:

5x30= 150

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vovangra [49]

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Answer:

a = m
b = n

Step-by-step explanation:

The axes of symmetry are shown and labeled m and n. Reflection across either (or both) axis of symmetry will map the figure to itself. Apparently, you want to designate those reflections as ...

Ra . . . where a = m

Rb . . . where b = n

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3 years ago

Read 2 more answers

Name the corresponding part if polygon WXYZ polygon PQRS.

MrRa [10]

The answer is RS since it in the same placing

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2 years ago

The reel good Cinema is conducting a mathematical study. In this theater, there are 200 seats. Adult tickets cost $12.50 and a c

denis23 [38]

Considering no discounts for bringing people to the theatre, and a being the number of adults attending the show and b the number of children attending the show then:

$1500 \leqslant 12.5a + 6.5b \leqslant 2500$

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2 years ago

Consider the function f(x, y) = x2 + xy + y2 defined on the unit disc, namely, D = {(x, y)| x2 + y2 ≤ 1}. Use the method of Lagr

a_sh-v [17]

Answer:________________________________________

Step-by-step explanation:

5 0

3 years ago

Suppose h(x)=3x-2 and j(x) = ax +b. Find a relationship between a and b such that h(j(x)) = j(h(x))

sergejj [24]

Answer:

$\displaystyle a = \frac{1}{3} \text{ and } b = \frac{2}{3}$

Step-by-step explanation:

We can use the definition of inverse functions. Recall that if two functions, f and g are inverses, then:

$\displaystyle f(g(x)) = g(f(x)) = x$

So, we can let j be the inverse function of h.

Function h is given by:

$\displaystyle h(x) = y = 3x-2$

Find its inverse. Flip variables:

$x = 3y - 2$

Solve for y. Add:

$\displaystyle x + 2 = 3y$

Hence:

$\displaystyle h^{-1}(x) = j(x) = \frac{x+2}{3} = \frac{1}{3} x + \frac{2}{3}$

Therefore, a = 1/3 and b = 2/3.

We can verify our solution:

$\displaystyle \begin{aligned} h(j(x)) &= h\left( \frac{1}{3} x + \frac{2}{3}\right) \\ \\ &= 3\left(\frac{1}{3}x + \frac{2}{3}\right) -2 \\ \\ &= (x + 2) -2 \\ \\ &= x \end{aligned}$

And:

$\displaystyle \begin{aligned} j(h(x)) &= j\left(3x-2\right) \\ \\ &= \frac{1}{3}\left( 3x-2\right)+\frac{2}{3} \\ \\ &=\left( x- \frac{2}{3}\right) + \frac{2}{3} \\ \\ &= x \stackrel{\checkmark}{=} x\end{aligned}$

3 0

2 years ago

Make Sense and Persevere What do you know? Whatare you trying to find?​

Make Sense and Persevere What do you know? Whatare you trying to find?