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Helga [31]
2 years ago
7

Which subject is used most heavily in game design?

Mathematics
2 answers:
harkovskaia [24]2 years ago
8 0

Answer:

nose

Step-by-step explanation:

perdno

Evgesh-ka [11]2 years ago
4 0

Answer:

Language arts

Step-by-step explanation:

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The sum of two numbers is 75. The second number is 3 less than twice the first
Mandarinka [93]

Answer:

\large{\textbf{The two numbers are: 26 and 49}.\\}

Step-by-step explanation:

\large{\textup{assume the two numbers are $x$ and $y$.}}\\\large{\textup{The given sentences are written in mathematical terms as follows:}\\$$ x + y =  75  \hspace{25mm} (1)$$ $$ y = 2x - 3 \hspace{25mm} (2) $$  \\\textup{Substituting $(2)$ in $(1)$,}\\\begin{align*} &  \implies x + 2x - 3 = 75  \\& \implies 3x = 78 \\& \implies x = 26\end{align*}\textup{Substituting $x$ in $(1), \hspace{5mm} y = 49$} }

7 0
3 years ago
Find the absolute and local maximum and minimum values of f . (Enter your answers as a comma-separated list. If an answer does
larisa86 [58]

Answer:

f(t)=4cos(t), â3Ï/2â¤tâ¤3Ï/2

Step-by-step explanation:

6 0
3 years ago
Factorising quadratics <br><br> All questions please to be completed. I’m stuck.
Alex777 [14]

Answer:

1. (x +1)(x - 1)

2. (x+5)(x-5)

3. (x+12)(x-12)

4. (x+14)(x-14)

5. (x+5)(x-7)

Step-by-step explanation:

The first 4 expressions can be factored with the difference of squares type of factoring.

For #5, the odd one out is (x+5)(x-7) because it isn't a factor of any of the standard form equations, while the others are

5 0
3 years ago
What is 3×1 and 3/5<br><br>A) 2 and 2/5<br>B) 4 and 3/5<br>C) 4 and 4/5<br>D) 7 and 4/5
Bas_tet [7]
Option C is your answer. 

1 3/5 is the same as 8/5

3(8/5) = 24/5 = 4 and 4/5
3 0
3 years ago
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
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