1.The measure of center that is most appropriate for this situation is the MEDIAN. This is because, one of the number given is an outlier, that is, it is much greater than the rest of the given numbers. If the mean of the number given is calculated, it will be discovered that the mean value obtained is higher than most of the scores in the data set, thus,the mean is not a suitable measure of central tendency in this case.
2. To find the median of the given numbers, arrange them in a descending order and add the two numbers in the middle then divide the value by 2.
That is, 0, 0, 1, 1, 2, 2, 2, 14.
The two numbers in the middle is 1 and 2.
Median = [1 + 2] / 2 = 3/2 = 1.5
Therefore, the median is 1.5
100 times, because 5 times 100 equals 500
Answer:
1)
82.5 - <u>8</u><u>2</u><u>.</u><u>5</u> + 2x = 338.5 - <u>8</u><u>2</u><u>.</u><u>5</u>
<u>2</u>x = <u>2</u><u>5</u><u>6</u>
2)
2x ÷ <u>2</u> = 256 ÷ <u>2</u>
x = <u>1</u><u>2</u><u>8</u>
Step-by-step explanation:
1)
In order to get rid 82.5, you have to substract the same value on both side to get a 0 value.
2)
In order to find the value of x, you have to divide the value that is sticked with x which is 2. As you divide 2 by 2, you will get 1 as a single value of x so you have to divide 2 to both side too.
Assume the girls sold X boxes in the first week. They sold in the second week X+5 and 2X+10 in the third week.
The sum X + X + 5 + 2X + 10 = 431
4X = 416. Therefore X = 104
The answers are:
a0 = 104
a1 = 109
a2 = 218
Hope that helps you :)
Are you sure you want ONLY the coefficient of b? If you expand this, you will have b in 3 of 4 terms.
According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:
1
1 2 1
1 3 3 1
1 4 6 4 1
So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
Here, you want (3 + b)^4. Here's what that looks like:
3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]
Which coeff did you want?
