Is my answer to question 4 correct? Only answer if you know FOR SURE!

Enter an equation in standard form for the line. Slope is -5, and (-6, -10) is on the line.

fredd [130]

Y+10=-5(x+6)
Y +10= -5x-30
5x+y+40=0

3 0

2 years ago

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A line passes through (−1, 7) and (2, 10).

Murljashka [212]

The formula is y=mx+b
To get the slope or m, use this formula
(the second y minus the first y)/(the second x minus the first x)
Now set it up.
(10-7)/(2--1)
3/3=slope is 1.
y=1x+b

Insert one of the points for x and y.
i will do (-1,7)
7=1(-1)+b
7=-1+b
8=b
Insert this into the final equation:
y=1x+8

Try it out. If you're not sure, try both points. If it works, then you set it up correctly.

6 0

3 years ago

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The diagram shows a stage in the construction of an angle bisector. Which sentence tells you how to perform the next step in the

Feliz [49]

Answer:

Draw intersecting arcs inside the angle from points D and E without changing the compass width.

Step-by-step explanation:

The next step from here, will be :

Draw intersecting arcs inside the angle from points D and E without changing the compass width.

After this, draw a straight line from B to the arcs made from above step. This line is the angle bisector.

5 0

2 years ago

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Let Ebe the set of all even positive integers in the universe Zof integers, and XE : Z R be the characteristic function of E.

AnnZ [28]

Answer:

$\mathbf{X_E (2) = 1}$

$\mathbf{X_E (-2) = 0 }$

$\mathbf{\{ x \in Z: X_E(x) = 1\} = E}$

Step-by-step explanation:

Let E be the set of all even positive integers in the universe Z of integers,

i.e

E = {2,4,6,8,10 ....∞}

$X_E : Z \to R$ be the characteristic function of E.

∴

$X_E(x) = \left \{ {{1 \ if \ x \ \ is \ an \ element \ of \ E} \atop {0 \ if \ x \ \ is \ not \ an \ element \ of \ E}} \right.$

For XE(2)

$\mathbf{X_E (2) = 1}$ since x is an element of E (i.e the set of all even numbers)

For XE(-2)

$\mathbf{X_E (-2) = 0 }$ since - 2 is less than 0 , and -2 is not an element of E

For { x ∈ Z: XE(x) = 1}

This can be read as:

x which is and element of Z such that X is also an element of x which is equal to 1.

∴

$\{ x \in Z: X_E(x) = 1\} = \{ x \in Z | x \in E\} \\ \\ \mathbf{\{ x \in Z: X_E(x) = 1\} = E}$

E = {2,4,6,8,10 ....∞}

5 0

2 years ago

For students who first enrolled in two year public institutions in a recent semester, the proportion who earned a bachelor's d

kondaur [170]

Answer:

Null hypothesis = $H_0:p=0.395$

Alternate hypothesis = $H_a:p>0.395$

Step-by-step explanation:

Given : In a recent semester, the proportion who earned a bachelor's degree within six years was 0.395.

The president of a certain college believes that the proportion of students who enroll in her institution have a higher completion rate.

To Find : Determine the null and alternative hypotheses.

Solution:

In a recent semester, the proportion who earned a bachelor's degree within six years was 0.395.

Claim : the proportion of students who enroll in her institution have a higher completion rate.

So,null hypothesis = $H_0:p=0.395$

Alternate hypothesis = $H_a:p>0.395$

6 0

2 years ago