Answer:
Here, l is the length of the rectangle and w is the width of the rectangle
To Compare the values, you must calculate each given situation.
Area of a rectangle is equal to length times width.
i.e, 
(A)
if l = 8 units and w= 6 units,
then;
= 
(B)
if l =7 units and w = 7 units
= 
Therefore, the Part B would yield a larger area.
If l -7 units and w = 7 units , the area of larger floor is 49 square units.
The first choice: <span>(x + 1)(x + 8)</span>.
1+8=9
1*8=8
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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Answer:
g(f): x -> 2(x-7)=2x-14 , g(f)(-1)=2*(-1)-14=-16
Step-by-step explanation:
Answer:
Ok, so the equation would be 6-2*12+5. The answer to that is -13.
Step-by-Step Explanation:
You would use PEMDAS. First, you multiply 2 and 12 and that's 24. Now your equation is 6-24+5. Then you subtract 6 and 24 and that's -18. Now your equation is -18+5, and the answer to that equation is -13. I hope this helps you!!
