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3 years ago

Which of the following arguments are valid? Explain your reasoning

Computers and Technology

1 answer:

klio [65]3 years ago

7 0

Answer:

a) the Statement is Invalid

b) the Statement is Invalid

Explanation:

lets Consider, s: student of my class

A(x): Getting an A

Let b: john

I have a student in my class who is getting ab A: Зs, A(s)

John need not be the student i.e b ≠ s could be true

Hence ¬A(b) could be true and the given statement is invalid

Lets Consider G: girl scout

C: selling 50 boxes of cookies

P: getting prize

s: Suzy

Now every girl scout who sells at least 50 boxes of cookies will get a prize: ∀x ∈ G, C(x) -> P(x)

Suzy, a girl scout, got a prize: s ∈ G, P(s)

since P(s) is true, C(s) need not be true

Main Reason: false → true is also true

Therefore the Statement is Invalid

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Alexxx [7]

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3 years ago

What is the magnitude of the largest positive value you can place in a bool? a char? an int? a float?

MaRussiya [10]

Answer:

A bool can hold only true or false values.

A char can hold maximum 65535 characters.

An int can hold maximum positive value of 2,147,483,647.

A float can hold maximum positive value of 3.4 x 10^{38}.

Explanation:

Primitive data types in Java language can be categorized into boolean and numeric data types.

Numeric can be divided further into floating point and integral type. Floating data type includes float and double values while and integral data type which consists of char, int, short, long and byte data types.

Every data type has a range of values it can hold, i.e., every data type has a minimum and maximum predefined value which it is allowed to hold. The intermediate values fall in the range of that particular data type.

Any value outside the range of that particular data type will not compile and an error message will be displayed.

The data types commonly used in programming are boolean, char, int and float.

A boolean variable can have only two values, true or false.

A char variable can hold from 0 to 65535 characters. Maximum, 65535 characters are allowed in a character variable. At the minimum, a char variable will have no characters or it will be a null char variable, having no value.

An int variable has the range from minimum -2^{31} to maximum 2^{31} – 1. Hence, the maximum positive value an int variable can hold is (2^{31}) – 1.

A float variable can hold minimum value of 1.4 x 10^{-45} and maximum positive value of 3.4 x 10^{38}.

The above description relates to the data types and their respective range of values in Java language.

The values for boolean variable remain the same across all programming languages.

The range of values for char, int and float data types are different in other languages.

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3 years ago

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Kitty [74]

Answer:

True

Explanation:

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3 years ago

Currently, this program will add 6 and 3 together, output the math problem and output the answer. Edit this code so that a rando

Yakvenalex [24]

I've included my code in the picture below. Best of luck.

6 0

3 years ago

Write a basic program that performs simple file and mathematical operations.

Ostrovityanka [42]

Answer:

Explanation:

I have written the Python program based on your requirements.

Just give the path of the input file and the path for the output file correctly where you want to place the output file.

In, my code - I have given my computer's path to the input and output file.

You just change the path correctly

My code works perfectly and I have tested the code with your inputs.

It gives the exact output that you need.

I have attached the Output that I got by running the below program.

Code:

month_list={ "january":"1","february":"2", "march":"3","april":"4", "may":"5", "june":"6","july":"7", "august":"8", "september":"9","october":"10", "november":"11", "december":"12"} input_file=open('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file=open('C:\\Users\\Desktop\\parsedDates.txt','w') for each in input_file: if each!="-1": lis=each.split() if len (lis) >=3: month=lis [0] day=lis[1] year=lis [2] if month.lower() in month_list: comma=day[-1] if comma==',': day=day[:len (day)-1] month_number=month_list[month.lower()] ans-month_number+"/"+day+"/"+year output_file.write (ans) output_file.write("\n") output_file.close() input_file.close()

- O X parsedDates - Notepad File Edit Format View Help 3/1/1990 12/13/2003

- X inputDates - Notepad File Edit Format View Help March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1

cheers i hope this helped !!

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4 years ago