Pls answer the question fasttt

Mathematics

2 answers:

marysya [2.9K]3 years ago

5 0

Divide both terms by 5:
5 ÷ 5 = 1
25 ÷ 5 = 5

Reducing to simplest form:
<span>5 : 25 = 1 : 5</span> I'm sorry if I'm wrong but I hope that I'm right

timurjin [86]3 years ago

3 0

5 : 25 → (÷5) → 1 : 5

Answer : 1 : 5

You might be interested in

Pluto is looking into joining a gym. He has a budget of $68 per month. The gym he wants to join has fees based on the number of

Artist 52 [7]

7(10 visits) ≤ 68
70 ≤ 68
Not Viable

7(9 visits) ≤ 68
63 ≤ 68
Viable

The first solution is not viable because 10 visits will give a total cost of $70 per month, which is $2 over his monthly budget of $68.

The second solution is viable. He could visit the gym a maximum of 9 times per month for a total of $63 a month and that will be under his $68 monthly budget.

Hope this helps! :)

6 0

3 years ago

What is the equation of the line that passes through the point (-6,-6) and has a slope of 2/3?

kotegsom [21]

Answer:

-6=2/3*-6

Step-by-step explanation:

y=mx+b

slope = m b=y intercept

6 0

3 years ago

A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. The number of subjects needed to estima

Ludmilka [50]

Answer:

$n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65$

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$