Answer:
1.) 0.54 ; 0.46
2.) 0.50 ; 0.40 ; 0.05 ; 0.85 ; 0.15
Step-by-step explanation:
A = feel guilty about wasting food ; P(A) = 0.39
B = feel guilty leaving lights on ; P(B) = 0.27
Probability of feeling guilty for doing both = 0.12
P(AnB) = 0.12
1a.) What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both (to 2 decimals)?
P(AuB) = P(A) + P(B) - P(AnB)
= 0.39 + 0.27 - 0.12
= 0.54
1b.) What is the probability that a randomly selected person will not feel guilty for either of these reasons (to 2 decimals)?
P(AuB)' = 1 - P(AuB)
P(AuB)' = 1 - 0.54
P(AuB)' = 0.46
2.)
n(ACC) = 10
n(SEC) = 8
n(total) = 20
n(ACC n SEC) = 1
a. What is the probability the ACC will have a team in the championship game (to 2 decimals)?
n(ACC) / n(Total) = 10 /20 = 0.50
b. What is the probability the SEC will have a team in the championship game (to 2 decimals)?
n(SEC) / n(Total) = 8/20 = 0.40
c. What is the probability the ACC and SEC will both have teams in the championship game (to 2 decimals)?
1 /20 = 0.05
d.)
P(AuB) = P(A) + P(B) - P(AnB)
= 0.50 + 0.40 - 0.05
= 0.85
e.)
P(AuB)' = 1 - P(AuB)
P(AuB)' = 1 - 0.85
= 0.15