Question

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Answer 1

Answer:

Δ ABC is similar to Δ DBE by Angle-Angle similarity postulate.

Step-by-step explanation:

See the attached diagram.

Given that, Line ED ║ Line CA

Now, between Δ ABC and Δ DBE

(i) ∠ DEB = ∠ ACB {Corresponding angles as BC is the transverse line}

(ii) Again, ∠ BDE = ∠ BAC {Corresponding angles as AB is the transverse line}

(iii) Again, ∠ B is the common angle.

Therefore, Δ ABC is similar to Δ DBE by Angle-Angle similarity postulate. (Answer)