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finlep [7]
4 years ago
14

Need help now !!! timed

Mathematics
1 answer:
Sphinxa [80]4 years ago
4 0

Answer:

Δ ABC is similar to Δ DBE by Angle-Angle similarity postulate.

Step-by-step explanation:

See the attached diagram.

Given that, Line ED ║ Line CA

Now, between Δ ABC and Δ DBE

(i) ∠ DEB = ∠ ACB {Corresponding angles as BC is the transverse line}

(ii) Again, ∠ BDE = ∠ BAC {Corresponding angles as AB is the transverse line}

(iii) Again, ∠ B is the common angle.

Therefore, Δ ABC is similar to Δ DBE by Angle-Angle similarity postulate. (Answer)

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Step-by-step explanation:

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