Answer:
Δ ABC is similar to Δ DBE by Angle-Angle similarity postulate.
Step-by-step explanation:
See the attached diagram.
Given that, Line ED ║ Line CA
Now, between Δ ABC and Δ DBE
(i) ∠ DEB = ∠ ACB {Corresponding angles as BC is the transverse line}
(ii) Again, ∠ BDE = ∠ BAC {Corresponding angles as AB is the transverse line}
(iii) Again, ∠ B is the common angle.
Therefore, Δ ABC is similar to Δ DBE by Angle-Angle similarity postulate. (Answer)
