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Katena32 [7]
3 years ago
5

What’s five million one hundred and six thousand and twenty in figures

Mathematics
1 answer:
MissTica3 years ago
5 0

Answer:

5,106, 020

Step-by-step explanation:

5 is in the millions spot, thousands in the thousands spot, and 20 in the twenty spot

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Jason’s budget is shown in the circle graph below. His total monthly budget is $3,000. How much does Jason spend on groceries? A
bonufazy [111]

Answer:

D.$750

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Lines a and b are parallel.
VashaNatasha [74]
I have added a screenshot with the complete question along with a diagram representing the scenario.

<u><em>Answer:</em></u>
s = 22°

<u><em>Explanation:</em></u>
<u>1- getting the top right angle of line B:</u>
We are given that:
the top right angle of line A = 158°
Since lines A and B are parallel, therefore, the top right angle of line A and the top right angle of line B are corresponding angles which means that they are equal
This means that:
<u>Top right angle of line B = 158°</u>

<u>2- getting the value of s:</u>
Now, taking a look at line B, we can note that:
angle s and the top right angle form a straight angle. This means that the sum of these two angles is 180°
Therefore:
180 = s + 158
s = 180 - 158
<u>s = 22°</u>

Hope this helps :)

8 0
3 years ago
I need help with this question
timofeeve [1]

Answer:

67 people i believe. I am not 100% sure..

Step-by-step explanation:

3 0
3 years ago
Use the cubic model y = 5a3 - 2a2 + a - 45 to find the value of y when x = 4.
Naddik [55]

Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.

3 0
3 years ago
Evaluate k to the 6th power times p to the -7 power when k is 2 and p is -1
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\bf ~~~~~~~~~~~~\textit{negative exponents}&#10;\\\\&#10;a^{-n} \implies \cfrac{1}{a^n}&#10;\qquad \qquad&#10;\cfrac{1}{a^n}\implies a^{-n}&#10;\qquad \qquad a^n\implies \cfrac{1}{a^{-n}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;k^6p^{-7}~~&#10;\begin{cases}&#10;k=2\\&#10;p=-1&#10;\end{cases}\implies (2)^6(-1)^{-7}\implies \cfrac{2^6}{(-1)^7}\implies \cfrac{64}{-1}\implies -64

7 0
3 years ago
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