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3 years ago

What is the measurement of each of the exterior angles of a regular pentagon?

Mathematics

1 answer:

valina [46]3 years ago

6 0

Remember that the degree measure of each exterior angle of a polygon can be found through the formula

$\dfrac{360}{n}$

where $n$ is the number of sides on the polygon.

Since a pentagon has five sides, the degree measures of each of its five sides would be:

$\dfrac{360}{5} = 72^{\circ}$

Thus, our answer is Choice B, or 72 degrees.

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City x has a population of 3x10 to the fifth power. City y has a population of 6x10 to the sixth power. Which statement correctl

SVEN [57.7K]

Answer:

Step-by-step explanation:

because it is 3x10 to the 5th power there woould be 5 zeros

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3 years ago

Write 9/12 as a sum of unit fractions

Svetlanka [38]

9/12=1/2+1/4 hope this helps

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4 years ago

a rectangles width is 11 feet more than its length if the perimeter is 54 feet what is the length and width ?

Sloan [31]

Answer:

Width = Length + 11

Perimeter:

(2 × Width) + (2 × Length) = 54 Feet

Substitute Width = Length + 11,

(2)(Length + 11) + (2 × Length) = 54

Length + 11 + Length = 54 ÷ 2

2Length + 11 = 27

2Legth = 27 - 11 = 16

Length = 16 ÷ 2 = 8

Width = 8 + 11 = 19

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3 years ago

E) A department store has marked down its merchandise by 25%. It later decreases by $5

Finger [1]

A. f(x) = 0.75xb. g(x) = x - 5c. $88.75d. Yes, if you do f(x) before g(x) or g(x) before f(x), you get different final prices.

8 0

3 years ago

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = 5y cos(z) i + ex sin(z) j + xey k, S is the hemisphere x2 + y2 + z2

Alenkinab [10]

By Stokes' theorem, the integral of the curl of $\vec F$ across $S$ is equal to the integral of $\vec F$ along the boundary of $S$ , call it $C$ . Parameterize $C$ by

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath$

with $0\le t\le2\pi$ . So we have

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

$=\displaystyle\int_0^{2\pi}(10\sin t\cos 0\,\vec\imath+e^{2\cos t}\sin0\,\vec\jmath+2\cos t\,e^{2\sin t}\,\vec k)\cdot(-2\sin t\,\vec\imath+2\cos t\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^{2\pi}-20\sin^2t\,\mathrm dt$

$=\displaystyle-10\int_0^{2\pi}(1-\cos2t)\,\mathrm dt=\boxed{-20\pi}$

6 0

4 years ago