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Dvinal [7]
4 years ago
9

Solve -12-3y+9=8y+6-y

Mathematics
1 answer:
nydimaria [60]4 years ago
8 0

Answer:

Step-by-step explanation:

add three y to eight y. then subtract six from nine.

-12+3=11y-y

9=10y

i don’t know what answer you’re going for but it’s either 9=10y or y=1

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Please help with these two! Take your time.
Nataly_w [17]

Answer:

#7=1360

#9=6802

Step-by-step explanation:

#7:25%=340

100x340 divided by 25%


<h2>#9:76% of 8950=6802</h2><h2>76/100x8950=6802</h2>
8 0
3 years ago
Read 2 more answers
A point located at (0, -6) is the same distance from 0 as the point located at (0, 6). True or False
Volgvan

Check the picture below.

7 0
4 years ago
PLS HELP OF AREA ON TRIANGLE!!!
azamat

Answer:

Area for Triangle is: 1/2bh or bh/2

Area for Trapezoid (As shown in picture):

1/2h(b1+b2)

You’d have to do 1/2 x 18(15+37) for the quesyion in the picture

Hope this helped!

3 0
3 years ago
Read 2 more answers
-3x+7=28 what am i supposed to do once i get it to be -3x=21
Brums [2.3K]

Answer:

You would divide by -3, in this case x would be -7

Step-by-step explanation:

-3/-3 = x -3/21 = -7

x=-7

4 0
2 years ago
A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(
Volgvan

Answer:

The number of ways of selecting of n items form r different items =^{(n+r-1)}C_{(r-1)}

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = ^{(32+5-1)}C_{(5-1)}

                                                               = ^{36}C_{4}

                                                                 = \frac{36!}{4!(36-4)!}

                                                                 = 58905

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = ^{(27+5-1)}C_{(5-1)}

                                                               = ^{31}C_{4}

                                                                 = \frac{31!}{4!(31-4)!}

                                                                 = 31465

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = ^{(22+5-1)}C_{(5-1)}

                                                               = ^{26}C_{4}

                                                                 = \frac{26!}{4!(26-4)!}

                                                                 = 14950

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0
4 years ago
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