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3 years ago

Factor 6x? + x – 12 by grouping. C

Mathematics

1 answer:

Semenov [28]3 years ago

7 0

Answer:

6x² + x - 12 = (2x + 3) (3x - 4)

Step-by-step explanation:

Factor 6x² + x - 12 by grouping

we need to rewrite the middle term as a sum of two terms whose product is (6* −12) = −72 and whose sum is 1

The middle term = x = 9x - 8x

6x² + x - 12

= 6x² + 9x - 8x - 12 Grouping the first two terms and the last two terms

= (6x² + 9x) + ( - 8x - 12)

From the first two terms take 3x as a common and from the two terms take (-4) as a common

= 3x ( 2x + 3) -4 (2x + 3)

Take (2x + 3) as a common

= (2x + 3) (3x - 4)

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3 years ago

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3 years ago

The (greatest, least) of the common factors of 2 or more numbers is the (greatest, least) common factor of the numbers.

Liula [17]

Answer:

The greatest of the common factors of 2 or more numbers is the greatest common factor of the numbers.

Step-by-step explanation:

As we know that

The greatest common factor of two or more whole numbers is the largest whole number that divides evenly into each of the numbers.

Thus, the greatest of the common factors of 2 or more numbers is the greatest common factor of the numbers.

For example, lets find the greatest common factor of $36$ and $54$ .

The possible factors of $36$ are:

1, 2, 3, 4, 6, 9, 12, 18, and 36.

The possible factors of $54$ are:

1, 2, 3, 6, 9, 18, 27, and 54.

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$1, 2, 3, 6, 9, 18$

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3 years ago

6) The amount of Jen's monthly phone bill is normally distributed with a mean of $70 and a standard

alexandr402 [8]

Answer:

i)The correct option is D.) 99.74%

ii) The correct option is B.) 68.26%

Step-by-step explanation:

i) P(10≤X≤70) = P( (10−40)/10 ≤Z≤ (70−40 )/10 ) = Pr(−3≤Z≤3)

= 0.9987 - 0.0013 = 0.99734

Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%

ii)P(2.1≤X≤3.1) = P( (2.1 − 2.6) /0.5 ≤ Z ≤ (3.1−2.6 )/0.5) = Pr(−1 ≤Z ≤1) )

= 0.8413 − 0.1587 = 0.6826

Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%

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3 years ago