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Svetach [21]
3 years ago
10

Find two consecutive even integers whose sum is 22

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

10 & 12

x = 1st consecutive even number

x + 2 = 2nd consecutive even number  

x + x + 2 = 22

2x + 2 = 22

2x = 20

x = 10

x + 2 = 12

10 and 12 are the two consecutive even numbers



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What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9?
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The vertex only relies on "a" and "b" though, so that +9 doesn't really matter in this case.  The vertex of a parabola is located where 
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Evaluate the double integral.
Fynjy0 [20]

Answer:

\iint_D 8y^2 \ dA = \dfrac{88}{3}

Step-by-step explanation:

The equation of the line through the point (x_o,y_o) & (x_1,y_1) can be represented by:

y-y_o = m(x - x_o)

Making m the subject;

m = \dfrac{y_1 - y_0}{x_1-x_0}

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

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m = 1

Thus;

y - 1 = (1)x

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The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

m = \dfrac{1-2}{4-1}

m = \dfrac{-1}{3}

∴

y-2 = -\dfrac{1}{3}(x-1)

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg)   dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy

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\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ([y^2(-4y+8)] \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( -4y^3+8y^2 \bigg ) \ dy

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4 0
2 years ago
Nevaeh invested $660 in an account paying an interest rate of 3% compounded
iris [78.8K]

Answer:

19

Step-by-step explanation:

Rate 1: 3  

4

1

​  

%=3+1/4=

\,\,3.25\%\rightarrow 0.0325

3.25%→0.0325

\text{Rate 2: }3\tfrac{1}{8}\%=3+1/8=

Rate 2: 3  

8

1

​  

%=3+1/8=

\,\,3.125\%\rightarrow 0.03125

3.125%→0.03125

\text{Calculate Final Amount for Nevaeh}

Calculate Final Amount for Nevaeh

\overline{\phantom{\text{Calculate Final Amount for Nevaeh}}}

Calculate Final Amount for Nevaeh

 

\text{Compounded Continuously:}

Compounded Continuously:

A=Pe^{rt}

A=Pe  

rt

 

P=660\hspace{35px}r=0.0325\hspace{35px}t=14

P=660r=0.0325t=14

Given values

A=660e^{0.0325(14)}

A=660e  

0.0325(14)

 

Plug in

A=660e^{0.455}

A=660e  

0.455

 

Multiply

A=1040.2744

A=1040.2744

Use calculator (with e button)

\text{Calculate Final Amount for Jonathan}

Calculate Final Amount for Jonathan

\overline{\phantom{\text{Calculate Final Amount for Jonathan}}}

Calculate Final Amount for Jonathan

 

\text{Compounded Monthly:}

Compounded Monthly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

 

Compound interest formula

P=660\hspace{35px}r=0.03125\hspace{35px}t=14\hspace{35px}n=12

P=660r=0.03125t=14n=12

Given values

A=660\left(1+\frac{0.03125}{12}\right)^{12(14)}

A=660(1+  

12

0.03125

​  

)  

12(14)

 

Plug in values

A=660(1.0026042)^{168}

A=660(1.0026042)  

168

 

Simplify

A=1021.6468

A=1021.6468

Use calculator

\text{How much more money Nevaeh has:}

How much more money Nevaeh has:

1040.2744-1021.6468

1040.2744−1021.6468

18.6276

18.6276

\$ 19

$19

4 0
3 years ago
3 + 3 x 3 - 3 + 3 =?
SCORPION-xisa [38]
12, 3x3 = 9, +3 =12-3=9+3=12
3 0
3 years ago
Read 2 more answers
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