Hey, the answer is no. A rectangle has 4 90 degree angles as all sides are equal.
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The length of the 3 sides
has a total dimension of 720 ft. One dimension, the length l, only has one side
enclosed. The other dimension, the width w, has 2 sides enclosed. So,
720 ft = l + 2w
Rearranging in terms of l:
l = 720 - 2w
Then the area equals
length times width, or:
A = (720-2w)(w) = 720w - 2w^2
To get the maximum area, we take the derivative of the Area
equation and set the derivative equal to 0: dA/dw = 0
dA/dw = 720 - 4w = 0
720 - 4w = 0
4w = 720
w = 180 ft
Calculating for l:
l = 720 – 2w
l = 720 – 2(180)
l = 360 ft
Therefore to get the
maximum enclosed area, the width (2 sides) should be 180 ft while the length (1
side) is 360 ft.<span>
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Answer:
AB=sqrt(53)
Step-by-step explanation:
consider the right angle triangle of the top rectangle w sides of 6 n 4
diagonal^2 = 6^2 + 4^2
consider the right angle triangle of the diagonal, AB and 1
AB^2 = diagonal^2 + 1^2
= 6^2 + 4^2 + 1^2
= 36 + 16 + 1
=53
AB=sqrt(53)
ans is a
It is just p3/p2 simplified