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faltersainse [42]
3 years ago
9

Two students in your class, Wilson and Alexis, are disputing a function. Wilson says that for the function, between x = –1 and x

= 1, the average rate of change is 0. Alexis says that for the function, between x = –1 and x = 1, the graph goes up through a turning point, and then back down. Explain how Wilson and Alexis can both be correct, using complete sentences.
What is the equation of the parabola? (I think it's a parabola)
Mathematics
1 answer:
nignag [31]3 years ago
8 0
Wilson can be correct because the functions x=-1 and x=1 are linear functions with no slope (no rate of change). The average y value of these functions is zero. Another function that has an average y value of 0 and no rate of change would be the function x=0. Since all of the y values of this function are 0, there is no rate of change and the average y value is zero itself is zero. Therefore, Wilson is correct. The function that Alexis described is a sinusoidal function. The equation for the function that Alexis described is f(x)=sin(x). The natural sinusoidal function oscillates around the average y=0 with maximums at y=-1 and y=1. A sinusoidal function goes up through a turning point and comes back down, and given this, Alexis is also correct.
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A contractor records all of the bedroom areas, in square feet, of a five-bedroom house as: 100, 100, 120, 120, 180 What is the v
kifflom [539]
The variance is the total of the squared distances of the given data from the mean. 

This can be calculated through the equation,
        
                            σ² = summation of X² / N  - μ²

where σ² is the variance X's are the data, N is the number of terms, and μ is the mean.

   summation of X² = 100² + 100² + 120² + 120² + 180² = 81200
                          N = 5
                                        μ = (100 + 100 + 120 + 120 + 180) / 5
                                         μ = 124

Substituting these values to the equation for variance,
                                 
                              σ² = (81200/5) - 124² = 864

Thus, the variance is equal to 864. 
4 0
3 years ago
Read 2 more answers
Given f(x)= x + 6 and g(x) = 12X –7, what is f(x) + g(x)?
quester [9]
13x-1
Is the answer, you have to get all you terms that being x+6+12x-7
6-7=-1
X+12x=13x
Put them together with the Xs first
13x-1
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Determine the Intercepts of the line.<br><br> Y-intercept: (__,__)<br> X-intercept: (__,__)
vagabundo [1.1K]

Answer:

I think the answer is 0.3 in 0.4

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3 years ago
When this 3-digit number is rounded to the nearest hundred, it rounds to 200.  Rounded to the nearest ten, this number rounds to
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Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
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