9- -3=12
2-2=0.
Slope is 12/0
The equation of a circle with center (h,k) and radius r is
(x-h)²+(y-k)²=r²
so
given center is (3,-4)
(x-3)²+(y-(-4))²=r²
(x-3)²+(y+4)²=r²
find r² by subsitutiong the point taht it passes through which is (6,5)
so
(6-3)²+(5+4)²=r²
3²+9²=r²
9+81=r²
90=r²
so
(x-3)²+(y+4)²=90 is da equation
4th equation
Answer:
<h3>Both are correct</h3>
Step-by-step explanation:
All the sides of an equilateral triangle are equal. Hence;
Perimeter of an equilateral triangle = 3S
S is one of the side length
Given;
S = 4n-2
Perimeter of the triangle = 3(4n-2)
This can also be expressed as P = S + S + S
P = (4n-2) + (4n-2) + (4n-2)
This shows that both methods are correct
