Let $A be the cost of $q of merchandise under plan A and similarly $B under plan B.
A=120+0.80q, B=40+0.90q
When A=B, 120+0.80q=40+0.90q, 80=0.10q, q=80/0.10=$800.
So you would need to buy $800 of merchandise.
A=B=120+640=40+720=$760 for each plan.
Answer:
v(9)=2000
V(15)=8000
Step-by-step explanation:
Answer
0.975 is the probability value
Step-by-step explanation:
We start by getting the z score of 86
z-score = (x - mean)/SD
z-score = (86-98)/6 = -12/6 = -2
So we want to find the probability of z greater than or equal to 2
We shall be using the standard normal distribution table here
We have the answer as;
0.975
Answer:
Step-by-step explanation:
(16*16)+(8*8)
16. 8
16. 8
—————-
96. 64
160
—————-
256+64=320