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3 years ago

Evaluate : 5-3(x-1) when x=7

Mathematics

2 answers:

Andrei [34K]3 years ago

7 0

Answer:

<h3> $\boxed{ \bold{ \boxed{ \sf{ - 13}}}}$ </h3>

Step-by-step explanation:

Given , x = 7

let's find :

$\sf{5 - 3(x - 1)}$

Plug the value of x

⇒ $\sf{5 - 3(7 - 1)}$

Subtract 1 from 7

⇒ $\sf{5 - 3 \times 6}$

Multiply the numbers

⇒ $\sf{5 - 18}$

Calculate

⇒ $\sf{ - 13}$

Hope I helped!

Best regards!!

Serggg [28]3 years ago

6 0

Answer:

- 13

Step-by-step explanation:

5 - 3(x - 1) =

= 5 - 3(7 - 1)

= 5 - 3×6

= 5 - 18

= - (18 - 5)

= - 13

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Step-by-step explanation:

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3 years ago

An airplane is 1440 above a buoy in the ocean. The buoy is 15 miles away from the mainland What is the diagonal distance in mite

Crazy boy [7]

Answer:

1440.08 mi

Step-by-step explanation:

Pythagorean Theorem:

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3 years ago

Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF

drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

$\therefore m\angle A = m\angle B$ ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

$m\angle F=m\angle E=90\°$ ⇒2

Now In △ABE and △CBF

∠A = ∠C (from 1)

∠E = ∠F (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

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3 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

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3 years ago

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xz_007 [3.2K]

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3 years ago