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Deffense [45]
3 years ago
12

At a little known vacation spot taxi fares are a bargain. A 36 mile taxi ride takes 42 minutes and cost $25.20. You want to find

the cost of a 47 mile taxi ride. What unit price do you need?

Mathematics
2 answers:
arsen [322]3 years ago
8 0

Answer:

It cost $32.90 for a 47 mile taxi ride.

Step-by-step explanation:

We are given the following information in the question:

Length of taxi ride = 36 miles

Time taken by taxi ride = 42 minutes

Cost of taxi ride = $25.20

We have to find cost of a 47 mile ride.

In order to do so, we have to find the unit cost of distance covered by ride which is the unit cost per mile of the ride that is the cost for 1 mile of taxi ride.

Formula:

\text{Unit Cost} = \text{Cost for 1 mile of axi ride} = \displaystyle\frac{\text{Cost of taxi ride}}{\text{Distance covered by taxi ride}}

\text{Unit Cost} = \displaystyle\frac{25.20}{36} = \$0.7\text{ per mile}

Cost of a 47 mile ride =

\text{Unit cost}\times Distance \\0.7\times 47 = 32.9

Hence, it cost $32.90 for a 47 mile taxi ride.

katen-ka-za [31]3 years ago
7 0

it would cost $32.90

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shutvik [7]

Answer:

Step-by-step explanation:

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4 0
3 years ago
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A newspaper carrier has $5.40 in change. He has six more quarters than dimes but five times as many nickles as quarters. How man
BigorU [14]
X= number of dimes
x+6= number of quarters
5(x+6)= number of nickels
$5.40= 540 cents

Add the number of each coin and set it equal to the total in cents.


x + (x + 6) + 5(x + 6)= $5.40
multiply 5 by parentheses; change dollar total to cents

x + (x + 6) + (5 * x) + (5 * 6)= 540

x + (x + 6) + 5x + 30= 540
combine like terms

7x + 36= 540
subtract 36 from both sides

7x= 504
divide both sides by 7

x= 72 dimes

x + 6= 78 quarters

5(x + 6)= 390 nickels


CHECK
72 + 78 + 390= 540
540= 540


ANSWER: There are 72 dimes, 78 quarters and 390 nickels.

Hope this helps! :)
5 0
3 years ago
4. The Bulldog Theater charges $9.10 for each adult ticket and $7.75 for each student ticket. Mrs. Williams purchased 7 tickets
zhuklara [117]

Answer:

Two adult tickets and 5 student tickets

Step-by-step explanation:

Let a=adult tickets   Let s=student tickets

You know that each adult ticket is $9.10 and each student ticket cost $7.75. At the end, it cost $56.95 for both students and adults so the first equation should be 9.10a+7.75s=56.95. To get the second equation, you know that Mrs. Williams purchased 7 tickets in total that were both students and adults. Therefore, the second equation should be a+s=7. The two equations are 9.10a+7.75s=56.95

a+s=7.

Now, use substitution to solve this. I will isolate s from this equation so the new equation should be s=-a+7. Plug in this equation to the other equation, it will look like this 9.10a+7.75(-a+7)=56.95. Simplify this to get 9.10a-7.75a+54.25=56.95. Simplify this again and the equation will become 1.35a=2.70. Then divide 1.35 by each side to get a=2. This Mrs. Williams bought two adult tickets. Plug in 2 into a+s=7, it will look like this (2)+s=7. Simplify this and get s=5. This means Mrs. Williams bought five adult tickets. Therefore she bought 2 adult tickets and 5 student tickets.

Hope this helps

4 0
3 years ago
I’m currently having a rough time in my math class. Can anyone please help me out with some of my questions? It would be so appr
notka56 [123]

Answer:

whats the question

Step-by-step explanation:

5 0
3 years ago
How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?
defon
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(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1

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\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3

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4 0
3 years ago
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