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Deffense [45]
3 years ago
12

At a little known vacation spot taxi fares are a bargain. A 36 mile taxi ride takes 42 minutes and cost $25.20. You want to find

the cost of a 47 mile taxi ride. What unit price do you need?

Mathematics
2 answers:
arsen [322]3 years ago
8 0

Answer:

It cost $32.90 for a 47 mile taxi ride.

Step-by-step explanation:

We are given the following information in the question:

Length of taxi ride = 36 miles

Time taken by taxi ride = 42 minutes

Cost of taxi ride = $25.20

We have to find cost of a 47 mile ride.

In order to do so, we have to find the unit cost of distance covered by ride which is the unit cost per mile of the ride that is the cost for 1 mile of taxi ride.

Formula:

\text{Unit Cost} = \text{Cost for 1 mile of axi ride} = \displaystyle\frac{\text{Cost of taxi ride}}{\text{Distance covered by taxi ride}}

\text{Unit Cost} = \displaystyle\frac{25.20}{36} = \$0.7\text{ per mile}

Cost of a 47 mile ride =

\text{Unit cost}\times Distance \\0.7\times 47 = 32.9

Hence, it cost $32.90 for a 47 mile taxi ride.

katen-ka-za [31]3 years ago
7 0

it would cost $32.90

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Answer:

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p_v =P(t_9>10.349)=1.34x10^{-6}  

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Step-by-step explanation:

1) Data given and notation      

\bar X=51.6 represent the sample mean

s=1.1 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =48 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:      

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Alternative hypothesis:\mu > 48      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

Calculate the P-value      

First we find the degrees of freedom:

df=n-1=10-1=9

Since is a one-side upper test the p value would be:      

p_v =P(t_9>10.349)=1.34x10^{-6}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.        

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Rewrite using the commutative property of multiplication.

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