3 years ago

What is the steps to solve f(x)=x^2

Mathematics

1 answer:

denis-greek [22]3 years ago

8 0

Do you need a domain and range?

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Polygon ABCDEFGH will be dilated by a scale factor of 3.4 with the origin as the center of dilation to produce polygon A′B′C′D′E

Romashka [77]

What are the answer choices?

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3 years ago

The area of a sector of an circle of a radius 5 cm, formed by an arc of length is 3.5cm. what is the answer

Natali5045456 [20]

Answer:

8.75cm²

Step-by-step explanation:

First we need to find the angle subtended by the arc

L = theta/360 * 2pir

3.5 = theta/360 * 2*3.14(5)

3.5 = theta/360 * 31.4

theta/360 = 3.5/31.4

theta/360 = 0.11146

theta = 0.11146 * 360

theta = 40.13 degrees

Area of the sector = theta/360 * pir^2

Area of the sector = 40.13/360 * 3.14*25

Area of the sector = 40.13/360 * 78.5

Area of the sector = 8.75cm

Hence the area of the sector is 8.75cm²

5 0

3 years ago

Help thank you! loll

snow_tiger [21]

Answer:

I think the answer is A.

But I am not sure.

3 0

2 years ago

Copy the problems onto your paper, mark the givens and prove the statements asked. Given: ∠BTO ≅ ∠IWE WI ≅ BT , OW ≅ ET Prove: △

Varvara68 [4.7K]

Answer:

$\triangle BOT \cong \triangle IEW$

Step-by-step explanation:

We are given the following in the question:

$\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW$

We have to prove:

$\triangle BOT \cong \triangle IEW$

Proof:

$\text{In }\triangle BOT \text{ and } \triangle IEW$

we can write:

$\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}$

Hence, the two triangle are congruent by SAS congruency rule.

$\triangle BOT \cong \triangle IEW$

The attached image shows the two triangle.

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3 years ago

Which expression is equivalent to the given expression?

worty [1.4K]

Answer:

omg its simple guys

Step-by-step explanation:

do the math.

8 0

2 years ago