X(b+c)+3b+3c write the expression as a product of polynomials:
2 answers:
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Hey!
To solve this problem, we would really have to graph both equations.
<em>OPEN THE FIRST IMAGE</em>
The first image I provided was the image of this equation graphed: <span>y=2x+1
<em>OPEN THE SECOND IMAGE</em>
The second image I provided was the image of this equation graphed: </span><span>y=2x^2+1
<em>PLEASE DO NOT LOOK AT THE THIRD IMAGE YET!</em>
The first image has two points. One at ( -0.5, 0 ) and the other at ( 0, 1 ).
The second image has only one point, which is at ( 0, 1 ).
<em>OPEN THE THIRD IMAGE</em>
Now, when both are combined we see that they intersect at two points, which are ( 0, 1 ) and ( 1, 3 ).
So, our answer is...
<em>The ordered pairs that are the solution to the system are</em> </span><span>( 0,1 ) and ( 1,3 ).
Hope this helped!
- Lindsey Frazier ♥</span>
To solve this problem, we would really have to graph both equations.
<em>OPEN THE FIRST IMAGE</em>
The first image I provided was the image of this equation graphed: <span>y=2x+1
<em>OPEN THE SECOND IMAGE</em>
The second image I provided was the image of this equation graphed: </span><span>y=2x^2+1
<em>PLEASE DO NOT LOOK AT THE THIRD IMAGE YET!</em>
The first image has two points. One at ( -0.5, 0 ) and the other at ( 0, 1 ).
The second image has only one point, which is at ( 0, 1 ).
<em>OPEN THE THIRD IMAGE</em>
Now, when both are combined we see that they intersect at two points, which are ( 0, 1 ) and ( 1, 3 ).
So, our answer is...
<em>The ordered pairs that are the solution to the system are</em> </span><span>( 0,1 ) and ( 1,3 ).
Hope this helped!
- Lindsey Frazier ♥</span>