Question

From a candy machine a random handful of colored chocolate candies are dispensed with 2 quarters. In one turn the machine dispenses 3 blue candies, 5 red candies, and 4 yellow candies. If you hide them in your hand and drop them one at a time into the other hand to eat them, what is the probability that the first candy will be blue and the second candy will be yellow?

Answer 1

Answer:

the answer should be 1/11

Step-by-step explanation:

p(blue first) = 3/12

p(yellow second) = 4/11

so p = 3/12 x 4/11

1/11 is your probability