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2 years ago

Could you help me with these questions pls?

Mathematics

2 answers:

KIM [24]2 years ago

6 0

The answer for number 12 is 1.5

katovenus [111]2 years ago

4 0

Answer:

12. is 1 1/2

Step-by-step explanation:

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Express the ratio 425 miles on 17 gallons of gas as a unit rate

Mariulka [41]

The answer is 25:1 or 25 to 1. They are the same thing thought.

7 0

3 years ago

Read 2 more answers

I need help with question number 12. Can’t figure this answer. Tried for 1 hour.

o-na [289]

Answer:

2, 12

Step-by-step explanation:

LCM = Least common multiple

LCM of 2 and 12 is 12

2 4 6 8 10 12

LCM of 6 and 8 is 24

6 12 18 24

8 16 24

LCM of 3 and 8 is 24

3 6 9 12 15 18 21 24

LCM of 12 and 24 is 24

12 24

5 0

3 years ago

PLEASE HELP ME ON THIS AND SHOW UR WORK THX

swat32

When an exponential function is given as
f(x)=ab^x, and
knowing that b^0=1, that means that
f(0)=ab^0=a value of function when x=0, or the initial value.
In the case of
f(x)=20.b^x, f(0)=20.b^0 = 20 (initial value)

If b=1.2, then the hourly growth rate is (1.2-1)=0.2=20%.
If b=1.85, then the hourly growth rate is (1.85-1)=0.85=85%.

4 0

3 years ago

Person 1 writes internal operating procedures 3 times faster than Person 2. Most of the procedures took 30 minutes each to creat

ad-work [718]

Person 1 takes 3 hour 10 minutes to complete 9 procedures

Solution:

From given question,

Person 2 takes 30 minutes per procedure

Person 1 writes internal operating procedures 3 times faster than Person 2

So we get, Person 1 takes 3 times faster than Person 2

Person 1 takes 10 minutes per procedure

But two of the procedures for Person 1 took an hour each

So person 1 takes 60 minutes each for two of procedures ( since 1 hour = 60 minutes )

Calculate how long it took Person 1 to complete 9 procedures:

So for first 7 procedures person 1 would take 10 minutes per procedure and for last two procedures person 1 would take 60 minutes per procedure

$time $=7$ procedures $\times \frac{10 \text { minutes }}{1 \text { procedure }}+2$ procedure $\times \frac{60 \text { minutes }}{1 \text { procedure }}$$