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ivolga24 [154]
3 years ago
11

Shen needs 271 programs for the school play on Thursday. How many boxes of programs will he need, given that each box contains 3

5 programs?
Mathematics
1 answer:
lesantik [10]3 years ago
8 0
7 because if you divide it by 35, it's seven.
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I really need help with this answer can someone help?
valina [46]

Answer:

$7075 or 7718

Step-by-step explanation:

91100-6200=84900

84900/11= 7718.18181818 or rounded= 7718

(This is if the december month doesnt count.)

84900/12=7075

(If december is included.)

7 0
3 years ago
Read 2 more answers
I need help thank you.
Darina [25.2K]

Answer:

The answers and steps are in the picture

6 0
2 years ago
. Describe a way you can use graham crackers to demonstrate the division problem . Include the result in your description.
Digiron [165]

Answer:

You can split your cracker 4 ways. So each cracker is  now 4. Now split your cracker into 4ths, 5•4 = 20! Hope this helps!

Step-by-step explanation:

Your Crackers have those lines, and they split 4 ways. SO this helps make the problem easierto solve.


6 0
3 years ago
How do you put the equation 2x+y=2 into slope intercept form
Dahasolnce [82]

Answer:

Step-by-step explanation:

you put the equation in slope and intercept form by making y the subject of the formula

i.e

y = -2x + 2

-2 is the slope and 2 is the intercept

5 0
2 years ago
Read 2 more answers
It is estimated that the annual cost of driving a certain new car is given by the formula C = 0.37m + 2600 where m represents th
arsen [322]

Answer:

12000-14000 (in miles)

Step-by-step explanation:

We are given that the annual cost of driving a certain car is given by the formula

C=0.37m+2600

Where m=Represents the number of miles driven per year

C=Cost in dollars

We have to find the range of  miles that Jane  can drive her new car.

Range of budgets=$7040-$7780

Substitute C=$7040 in the given formula

7040=0.37m+2600

7040-2600=0.37m

4440=0.37m

m=\frac{4440}{0.37}

m=12000

Substitute C=$7780 in the given formula

7780=0.37m+2600

7780-2600=0.37m

5180=0.37m

m=\frac{5180}{0.37}=14000

The range of miles that Jane can drive her new car=12000-14000

4 0
3 years ago
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