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3 years ago

11

Shen needs 271 programs for the school play on Thursday. How many boxes of programs will he need, given that each box contains 3

5 programs?

1 answer:

lesantik [10]3 years ago

8 0

7 because if you divide it by 35, it's seven.

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If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750

maksim [4K]

Answer:

$\boxed {\boxed {\sf 250 \ people}}$

Step-by-step explanation:

Let's set up a proportion using the following setup.

$\frac {buses}{people}=\frac {buses}{people}$

We know 30 buses can carry 1,500 people.

$\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}$

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

$\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}$

$\frac {30 }{1500 }=\frac {5 }{x }$

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

$30*x=1500*5\\30x=7500$

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

$30x/30=7500\\x=250$

5 buses can carry 250 people.

7 0

3 years ago

Ik it’s pretty easy but u knowh am not really sure if am right or not

gladu [14]

2,6,18

r = 6/2 = 3

18 *3 = 54

54*3 = 162

162*3=486

Answer: 54,162,486

8 0

3 years ago

Read 2 more answers

Write the equation in standard form.<br><br> 3x−9=7y

Ket [755]

In standard form the answer will be if you go by (Ax+by=c )then I must say it's 3x-7y=9

6 0

2 years ago

NEED HELP ASAP MULTILPLICATION

Maru [420]

The answer is 15 13/15
yeah yep.

7 0

3 years ago

If 10^2y = 25, then 10^-y equals:<br>(a) -1/5<br>(b) 1/625<br>(c) 1/50<br>(d) 1/25<br>(e) 1/5

Gemiola [76]

<h3><u>given</u><u>:</u></h3>

<u> $10 ^{2y} = 25$ </u>

<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>

<u> ${10}^{y} = .......$ </u>

<h3><u>solution</u><u>:</u></h3>

<u> $10 ^{2y} = 25$ </u>

<u> $(10y {)}^{2} = {5}^{2}$ </u>

<u> $10y = 5$ </u>

<u> $\frac{1}{ {10}^{y} } = \frac{1}{5}$ </u>

<u> ${10}^{ - y} = \frac{1}{5}$ </u>

<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>option</u><u> </u><u>E</u><u>.</u>

8 0

1 year ago

Read 2 more answers