If the smaller number is x, then the larger number has to be 20 - x in order for the arithmetic mean to be 10, as their sum must be 20.
If the geometric mean is 8 the product of the numbers has to be 64 and so the larger number is 64/x
Solving 64/x = 20 - x gives the quadratic x^2 -20x +64 = 0 so x = 4 or 16.
The two numbers are 4 and 16.
A trapezoid does not have 2 pair of parallel sides so we can cross that out. A rhombus does not have right angles so cross that out. So we got A and C. A square has 2 pair of parallel lines and and 4 right angle. Your answers should be.
<span>C. Square
It could not be A. Most likely its C. So you can pick both or just C.</span>
Let the dimensions be x and y
Given that the area is 40m²
xy = 40 ----------------- (1)
Given that the perimeter is 26
2(x + y) = 26
x + y = 13
x = 13 - y ---------------- Sub into (1)
(13 - y)y = 40
13y - y² = 40
y² - 13y + 40 = 0
(y - 8)(y - 5) = =
y = 8 or y = 5
The dimensions are 8 meters and 5 meters
Simplify the equation.
First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7
Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7
Now simplify the right side of the equation by subtracting the 1 from the 7.
Resulting in: x + 6
Our goal is to isolate the x to the left side, and the numerals to the right side.
With that in mind, add the 6 (from the right side) to both sides. This cancels out the 6 on the right side.
Resulting in: 2x = 12
Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
Resulting in: x = 6
Hope this helps.
