3 years ago

38.96 to the nearest tenth

Mathematics

1 answer:

RUDIKE [14]3 years ago

6 0

39 , is your answer.

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compare the right-hand and left-hand derivatives to show that the function is not differentiable at the point P. find all points

Softa [21]

$f(x)= \left \{ {{ \sqrt{x} } \atop {2x-1}} \right. 
\\
\\ f'(x)= \left \{ {{ \frac{1}{2\sqrt{x}} } \atop {2}} \right. 
\\
\\ f'(1)= \left \{ {{ \frac{1}{2}} \atop {2}} \right. 
\\
\\ f'(1^-) \neq f'(1^+)$

Therefore, the function is not differentiable at x = 1.

$f(x)= \sqrt{x} 
\\
\\f'(x)= \frac{1}{2 \sqrt{x} } 
\\
\\f'(0)=\frac{1}{2 \sqrt{0} } = \infty$

Therefore, the function is not differentiable at x = 0.

3 0

3 years ago

12 + 54=6(_+_) <br><br> please help me 14 points but please just help me

sp2606 [1]

Are there any other details as to what the numbers are? otherwise there are six possibilities for this
12+54=66
66=6(_+_)
11=(_+_)

1) 0, 11
2) 1, 10
3) 2, 9
4) 3, 8
5) 4, 7
6) 5, 6

7 0

3 years ago

Read 2 more answers

Brainliest if correct

n200080 [17]

Answer:

16 and 125

Step-by-step explanation:

-2*-2 = 4

4*-2 = -8

-8*-2 = 16

5*5 = 25

25*5 = 125

6 0

2 years ago

Please help asap thx a bunch

Aloiza [94]

it would be high I think

3 0

3 years ago

Which two lines below are perpendicular lines?

Naily [24]

Answer:

You said never mind, but I really like your username :)

Step-by-step explanation:

6 0

2 years ago