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Rufina [12.5K]
3 years ago
5

In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD, while

point E is the point of intersection between segment AG and segment DF.
Prove ΔABC ∼ ΔGEF.

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

See Below.

Step-by-step explanation:

We are given that:

\angle ABC \cong \angle DEC\text{ and } \angle GFE \cong \angle DCE

By vertical angles:

\displaystyle \angle DEC\cong \angle GEF\text{ and } \angle DCE\cong \angle ACB

Hence, by substitution:

\displaystyle \angle ABC\cong \angle GEF\text{ and } \angle GFE\cong \angle ACB

Then by Angle-Angle Similarity:

\Delta ABC \sim \Delta GEF

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The drying times for a certain type of cement are normally distributed with a standard deviation of 30 minutes. A researcher wis
IceJOKER [234]

Answer:

h. 36

Step-by-step explanation:

For a 68.26% confidence, z = 1.0.

Standard deviation (s) = 30 minutes

The sample size needed to assure that the sample mean does not differ from the true mean by more than 5 minutes is given by:

5\geq z*\frac{s}{\sqrt n}\\\sqrt n\geq 1*\frac{30}{5}\\n\geq 36

The sample size needed is 36.

5 0
3 years ago
The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.D1d2, where d1 and d2 are the l
Gelneren [198K]

Answer:

d1=2A/d2

d2=2A/d1

Step-by-step explanation:

The options of this question are:

1. d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2Ad₁

Given:

A=1/2(d1*d2)

Multiply both sides by 2

We have,

2A=d1*d2

Divide both sides by d2

2A/d2=d1*d2/d2

2A/d2=d1

Therefore, d1=2A/d2

Similarly, from the previous equation

2A=d1*d2

Divide both sides by d1

2A/d1=d1*d2/d1

2A/d1=d2

Therefore,

d2=2A/d1

Options

2. d₁= 2A/d₂

4. d₁= 2A/d₂

7 0
3 years ago
Help me please please help
Vilka [71]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
Y+1=3(x−4)<br> Find the Y intercept and the X intercept
vivado [14]
X intercept-(9,2/0)
y intercept-(0,-9)
hope this helps
3 0
3 years ago
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