In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD, while
point E is the point of intersection between segment AG and segment DF.
Prove ΔABC ∼ ΔGEF.
1 answer:
Answer:
See Below.
Step-by-step explanation:
We are given that:

By vertical angles:

Hence, by substitution:

Then by Angle-Angle Similarity:

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