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Debora [2.8K]
3 years ago
5

2 women and 7 girls can do a peice of work in 4 days.4 women and 4 girls can do the same work in 3 days. How long would it take

for 1 women and 1 girl to do the work.
Mathematics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

x: work a woman can do in 1 day

y: work a girl can do in 1  day

Then

2x + 7y =1/4

4x + 4y =1/3

4x + 14y =2/4 (1)

4x + 4y  =1/3 (2)

=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)

=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)

=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)

Then, the day required for a woman and a girl to complete work: 12 days

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Hurry quick! If you know how to solve this please let me know step by step because I don't understand the material. Questions ar
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Answer:

x+y=29

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Step-by-step explanation:

the amount of tickets he sold is 29 which includes VIP and general admission tickets so the number of tickets sold for each would be x+y=29.

the price for general admission is 70$ and VIP is 80$. the profit from the tickets is 2130$ so that would be the number of general tickets (x) times the price (70) and the number of VIP tickets (y) times the price (80) so that would be 80y. therefore you're equation would be 70x+80y=2130. that is your system of equations.

To figure out the number of tickets for each: Solve x+y=29 for x:

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x=−y+29

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70x+80y=2130

70(−y+29)+80y=2130

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|3x - 5| = |6x - 1|
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Answer:

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