Answer:
Step-by-step explanation:
In the argand plane for plotting points of complex numbers we take i coefficient as x and j coefficient as y and plot as we plot regular points on the graph.
v=3i+2j
Point is (3,2) A
w =2i+3j , Point is (2,3) B
v+w = 5i +5j Point is (5,5) C
2w = 4i+6j , point is (4,6)
v-w = i-j Point (1,-1)
Please find enclosed the above points plotted on the graph.
Answer:
The slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.
Explanation:
Points given = ( -10, -8) and ( -8, -16)
Slope = ?
( -10, -8 ) : x1 = -10 and y1 = -8
( -8, -16 ) : x2 = -8 and y2 = -16
We know,
slope = y2 - y1 / x2 - x1
Slope = -16 - ( -8) / -8 - (-10)
slope = -16 + 8 / -8 + 10
slope = -8 / 2
slope = -4
Therefore, slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.
Step-by-step explanation:
The third option, 100*
making it an abtuse triangle
If incorrect, sorry
Answer:
40 square units
Step-by-step explanation:
This is a rhombus, so you multiply the two diagonals and divide by 2.
8x10÷2=40
Answer:
Step-by-step explanation:
The standard form of an equation of a line:
We have the equation in the point-slope form. Convert:
