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3 years ago

What type of expressions are in 3x–2y+7? I asked the wrong question beforehand.

Mathematics

1 answer:

nasty-shy [4]3 years ago

7 0

Answer:

Step-by-step explanation:

3x+2y=7

Simplifying

3x + 2y = 7

Solving

3x + 2y = 7

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

3x + 2y + -2y = 7 + -2y

Combine like terms: 2y + -2y = 0

3x + 0 = 7 + -2y

3x = 7 + -2y

Divide each side by '3'.

x = 2.333333333 + -0.6666666667y

Simplifying

x = 2.333333333 + -0.6666666667y

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zavuch27 [327]

<h2>Answer:</h2>

Let m<6 be X

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3 years ago

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(2, -3)

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3 years ago

28 + 2A = 5A + 7 Please explain thank you!

Vinvika [58]

First you need to get x on one side of the equation and to do that subtract 2a from both sides.
28 + 2a = 5a + 7
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28=3a+7

Then we need to get a alone by subtracting 7 on both sides.
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Finally divide each side by 3 and you should get a = 7. Hope this helps!

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3 years ago

A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia

iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}$

what's the population in 2004? well, from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004

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Sedbober [7]

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3 years ago