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4 years ago

How many particles are in a mole? 6.02 × 1023 23 × 106 602 billion 6.02 × 2310

Chemistry

2 answers:

Olin [163]4 years ago

7 0

Answer:

$.0x = 3201.90t \: y = 0.91834 \beta$

Explanation:

$\geqslant y | \sqrt[ = 8206m]{5294.6810t} | \times \frac{32.4}{y} = molecull \: of \: cell \: conduct \: is \: possible \: active \alpha$

Amanda [17]4 years ago

6 0

Answer:

$1mole=6.02x10^{23} unit$ (Avogadro constant)

Explanation:

It is known by the name of mole (mol) to one of the fundamental physical magnitudes that contemplate the International System of Units. This unit is used to measure the quantity of all kinds of substances present in a given system.

The mole, experts say, reflects the amount of substance that has a specific number of entities of elementary character as atoms can be found in twelve grams of carbon-12. This means that the number of elementary units (as in the case of atoms, molecules or ions, for example) that are reflected in a mole of substance is a constant that has no direct relationship with the type of particle or material in question. This amount is known as Avogadro's number.

This constant, baptized in homage to the scientist of Italian origin Amedeo Avogadro (1776-1856), allows to count microscopic particles from macroscopic measurements (as it is the case of the mass).

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A 200.0mL closed flask contains 2.000mol of carbon monoxide gas and 2.000mol of oxygen gas at the temperature of 300.0K. How man

max2010maxim [7]

Answer:

There will react 0.400 moles of oxygen.

Explanation:

Step 1: Data given

Volume of the closed flask = 200.00 mL = 0.2 L

Number of moles of CO = 2.000 mol

Number of moles of O2 = 2.000 mol

Temperature = 300.0 K

Pressure decreases with 10%

Step 2: The balanced equation

2CO(g)+O2(g)⟶2CO2(g)

Step 3: Calculate the initial pressure of the flask before the reaction

P = nRT/V

⇒ with n = the number of moles (2.000 moles CO + 2.000 moles O2 = 4.000 moles)

⇒ R is gas constant (0.08206 atm*L/mol*K)

⇒T = the temperature = 300.0K

⇒ V = the volume = 200.0 mL = 0.2 L

P = (4 * 0.08206*300)/0.2

P = 492.36 atm

Step 4: When the pressure is 10 % decreased:

The final pressure = 492.36 - 49.236 = 443.124 atm

Step 5: Calculate the number of moles

n = PV/RT

⇒ with n = the number of moles

⇒ with P = the pressure = 443.124 atm

⇒ V = the volume = 200.0 mL = 0.2 L

⇒ R is gas constant (0.08206 atm*L/mol*K)

⇒T = the temperature = 300.0K

n =(443.124*0.2)/(0.08206*300)

n = 3.6 moles = total number of moles

Step 6: Calculate number of moles

For the reaction :2CO(g) + O₂(g) ⟶ 2CO₂(g)

For each mole of O2 we have 2 moles of CO, to produce 2 moles of CO2

Moles CO = (2 -2X) moles

Moles O2 = (2-X) moles

Moles CO2 = 2X

The total number of moles (4 -X)= 3.6 moles

Where X are moles that react

X = 0.400 moles

There will react 0.400 moles of oxygen.

6 0

3 years ago

What is the ph of a 0.001 62 m naoh solution?

marin [14]

The answer
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =0.001 62
and for a strong basis, pH can be calculated as pH = 14 + log [ OH -]
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79

finally pH = 14 -2.79 = 11.20

4 0

3 years ago

In the mid-1900s, most scientists used the Bohr atomic model to study atoms. In the Bohr model, electrons move in set paths arou

Novosadov [1.4K]

The answer is c beca it true

5 0

3 years ago

Read 2 more answers

Please help I’m torn between A and B. I’ve asked many and people say A, but I asked my science teacher and she said B. And also

astraxan [27]

If your science teacher says B, it’s probably because water has a negative and positive end, heat is just a form of energy, as other atoms can’t leave (they’re attracted to the ends) they are being insulated; but notice that ice will melt into gas (where atoms have tons of space) for other atoms to escape. Hence ice and gas aren’t ideal. (Air is a gas here.)
It’s not a 100% but hopefully it helps with some kind of analogy.

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3 years ago

Which situation would not cause the following equilibrium to shift to the right

Elis [28]

If you’re talking about a reaction, an increase in the products (values on the right side of the chemical equation) would cause the reaction to shift left instead of right. Also a decrease in the reactants.

Also, could be wrong, but increasing the volume/ decreasing the pressure on the reactant side will cause the reaction to shift left

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4 years ago