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bonufazy [111]
4 years ago
8

How many particles are in a mole? 6.02 × 1023 23 × 106 602 billion 6.02 × 2310

Chemistry
2 answers:
Olin [163]4 years ago
7 0

Answer:

.0x = 3201.90t \: y = 0.91834 \beta

Explanation:

\geqslant y | \sqrt[ = 8206m]{5294.6810t} |  \times \frac{32.4}{y}  = molecull \: of \: cell \: conduct \: is \: possible \: active \alpha

Amanda [17]4 years ago
6 0

Answer:

1mole=6.02x10^{23} unit (Avogadro constant)

Explanation:

It is known by the name of mole (mol) to one of the fundamental physical magnitudes that contemplate the International System of Units. This unit is used to measure the quantity of all kinds of substances present in a given system.

The mole, experts say, reflects the amount of substance that has a specific number of entities of elementary character as atoms can be found in twelve grams of carbon-12. This means that the number of elementary units (as in the case of atoms, molecules or ions, for example) that are reflected in a mole of substance is a constant that has no direct relationship with the type of particle or material in question. This amount is known as Avogadro's number.

This constant, baptized in homage to the scientist of Italian origin Amedeo Avogadro (1776-1856), allows to count microscopic particles from macroscopic measurements (as it is the case of the mass).

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Explanation:

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8 0
3 years ago
Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell
olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0
3 years ago
What is the work done in lifting 60 kg of blocks to a height of 20 m
balandron [24]

Answer:

<h2>1200 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 60 × 20

We have the final answer as

<h3>1200 J</h3>

Hope this helps you

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