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puteri [66]
3 years ago
8

By using the following reactions, calculate the heat of combustion of pentane:

Chemistry
1 answer:
Sergio [31]3 years ago
6 0
To answer this problem, we use Hess' Law to calculate the overall enthalpy of the reactions. The goal is to add all the reactions such that the final reaction is C<span>5H12 (g) + 8O2 (g) → 5CO2 (g) + 6H2O (l) through cancellation adn multiplication. The first equation is multiplied by 5, the second one is multiplied by 6 and the third one is reversed. The final answer is -3538 J or -3.54 x10^3 kJ.</span>
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Calculate the number of miles of magnesium,chlorine, and oxygen atoms in 5.00 moles of magnesium perchlorate
Zigmanuir [339]

Answer:

5.00 mol Mg

10.0 mol Cl

40.0 mol O

Explanation:

Step 1: Given data

Moles of Mg(ClO₄)₂: 5.00 mol

Step 2: Calculate the number of moles of Mg

The molar ratio of Mg(ClO₄)₂ to Mg is 1:1.

5.00 mol Mg(ClO₄)₂ × 1 mol Mg/1 mol Mg(ClO₄)₂ = 5.00 mol Mg

Step 3: Calculate the number of moles of Cl

The molar ratio of Mg(ClO₄)₂ to Cl is 1:2.

5.00 mol Mg(ClO₄)₂ × 2 mol Cl/1 mol Mg(ClO₄)₂ = 10.0 mol Cl

Step 4: Calculate the number of moles of O

The molar ratio of Mg(ClO₄)₂ to Cl is 1:8.

5.00 mol Mg(ClO₄)₂ × 8 mol O/1 mol Mg(ClO₄)₂ = 40.0 mol O

4 0
3 years ago
Nick hypothesizes that wax has a higher melting point than chocolate how can he test his hypothesis
LUCKY_DIMON [66]
Melt chocolate and measure the temperature and then melt wax and measure the temperature and compare his results.
5 0
3 years ago
Calculate the volume of a cube with the following measurements length= 5cm height =10 cm width=16 cm
Anna35 [415]

Answer:

800 cubic cm

Explanation:

3 0
2 years ago
An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola
liq [111]

<u>Answer:</u> The molality of NaC_2H_3O_2 solution is 0.782 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}} .....(1)

Given values:

Moles of NaC_2H_3O_2 = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m

Hence, the molality of NaC_2H_3O_2 solution is 0.782 m

8 0
2 years ago
Can someone please help me answer these questions and I’ll give you brainlest!!!!!
pickupchik [31]

Explanation:

first of all open the menu

5 0
2 years ago
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