Answer:
The sum of 2+4+6+8+...+250 will be: 22650
Step-by-step explanation:
Given
2+4+6+8+...+250
2(1+2+3+4+...+150)....[A]
Considering the sequence
1+2+3+4+...+150
Lets calculate the sum of first 150 terms
So the sequence is Arithmetic.
as
and
So the sum of first 150 terms of the arithmetic
sequence 1+2+3+4+...+150 is: 11325
Now, according to expression [A], multiply 11325 by 2 to determine the sum of 2+4+6+8+...+250.
As
1+2+3+4+...+150 = 11325
Thus
2(1+2+3+4+...+150) = 2(11325) = 22650
Therefore, the sum of 2+4+6+8+...+250 will be: 22650
2x-y+2=0
slope=y-y/x-x
6-(-6)/2-(-4)=2
eq=Y-y/X-x
y-6/x-2=2
2x-4=y-6
2x-y+2=0
7/8 is already a fraction
Answer:
Answer is option b and c and d
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<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
I am assuming your teacher wants you to solve for v.
Therefore we need to isolate v, first step will be moving 2 to the other side then multiplying both sides by 11.
4=v/11-2
4+2=v/11
6=v/11
6*11=v/11*11
66=v
v=66
Check answers: substitute v=66 back into the equation.
right hand side:66/11-2=6-2=4
left hand side:4
RHS=LHS therefore the solution is correct.
Done!
Hope this helped, if there are any questions just ask them in the comments and I will answer them.
