Let p and q be different prime numbers. How many positive factors will (p^2 * q^4)^3 have?

Mathematics

2 answers:

Naily [24]3 years ago

7 0

Answer:

Step-by-step explanation:

p^6×q^12 will have (6+1)(12+1) = 7×13 = 91 positive integer divisors.

Aliun [14]3 years ago

5 0

The answer would be 91.

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