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KatRina [158]
3 years ago
7

The base of an exponential model is 1.024. Is the base a growth or decay factor , why or why not?

Mathematics
2 answers:
g100num [7]3 years ago
5 0
<h2>Answer:</h2>

According to the base of the exponential function which is given to us we get that it is the base of a growth factor.

<h2>Step-by-step explanation:</h2>

We know that a exponential function is in general represented by the expression:

                     f(x)=ab^x

where a is the initial amount; a>0

b is the base of the exponential function.

Also, the exponential function is a growth function is b>1

and it represent a decay if 0<b<1

Here we have:

Base i.e. b=1.024>1

Hence, it will represent  a growth function.

PtichkaEL [24]3 years ago
4 0
I think it depends on the depends on what result you are looking for if it is the exponential model used in the problem. In this problem, it does show how someone gets this results. Both the exponential growth and decay can be used in exponential functions.
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LiRa [457]

Answer:

X represents The value of players on the field

Step-by-step explanation:

the numbers 0-11 are showing how many people would be on the field should an official game be played

7 0
2 years ago
What is the slope line perpendicular to the equation 4x+3y=9
aleksandrvk [35]

Answer:

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

7 0
3 years ago
How many trucks carried only late variety?
murzikaleks [220]

9514 1404 393

Answer:

  • late only: 15
  • extra-late only: 24
  • one type: 43
  • total trucks: 105

Step-by-step explanation:

It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.

For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.

Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.

__

a) 15 trucks carried only late

b) 24 trucks carried only extra late

c) 4+15+24 = 43 trucks carried only one type

d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out

8 0
3 years ago
HELP QUICK.
lakkis [162]
Pretty sure it’s C That one makes the most sense to me please let me know if you get it right
5 0
2 years ago
Read 2 more answers
What are the roots to<br> the equation<br> 2x² + 6x-1=0?
lys-0071 [83]

Answer:

The roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}    

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = \frac{ - b}{a}

And products of roots = \frac{c}{a}

So, m + n = \frac{ - 6}{2} = - 3

And m × n =  \frac{ - 1}{2}

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 (\frac{ - 1}{2})

Or, (m - n)² = 9 + 2 = 11

I.e m - n = \sqrt{11}

Again m + n = - 3    And m - n = \sqrt{11}

Solving this two equation

(m + n) + ( m - n) = - 3 + \sqrt{11}

I.e 2 m =  - 3 + \sqrt{11}

Or, m = \frac{-3}{2} + \frac{\sqrt{11} }{2}

Similarly n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      

Hence the roots of  equations are as m =  \frac{-3}{2} + \frac{\sqrt{11} }{2}  And n =  \frac{-3}{2} - \frac{\sqrt{11} }{2}      Answer

6 0
3 years ago
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