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3 years ago

How do you round 1/3 to the nearest penny

1 answer:

6 0

1/3 in decimal form is 3.3 (repeating)
So, rounding it to the nearest penny would be rounding it to the hundredths place which would be 3.33.

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A right cylinder has a radius of r inches and height of 2r inches. In terms of r, the lateral area of the cylinder is r2π square

cupoosta [38]

Answer: 4, 2 and 6

Step-by-step explanation:

I just did it

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3 years ago

Solve the following system: (5 points)

posledela

I wish I could help but I didn’t learn that

5 0

3 years ago

Read 2 more answers

a triangular poster is 3 times as long as its height. The coaster has an area of 24 in. What are the dimensions of the poster?

Bas_tet [7]

Answer:

Step-by-step explanation:

I got this from timing 24×3 and you may ask how do u times it together well first start off with 4×3 and u get 12 then times 3×2 and u get 6 + 1 more u get 7 so that's how I got 72 for answer

3 0

4 years ago

If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e

Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

99 is an outlier of pet group
See attachment for the parallel box plots

(a) Prove that 99 is an outlier for Pet

We have:

Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99

$n = 15$

The quartiles positions are:

$Q_1 = \frac{n + 1}{4}$

$Q_1 = \frac{15 + 1}{4}$

$Q_1 = \frac{16}{4}$

$Q_1 = 4th$

$Q_3 = Q_1 \times 3$

$Q_3 = 4th \times 3$

$Q_3 = 12th$

So, we have:

$Q_1 = 4th$

$Q_3 = 12th$

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

$Q_1 = 68$

$Q_3= 79$

The lower and upper limits of the outlier are:

$L = Q_1 - 1.5 \times (Q_3 - Q_1)$

$U = Q_3 + 1.5 \times (Q_3 - Q_1)$

So, we have:

$L = 68 - 1.5 \times (79 - 68)$

$L = 51.5$

$U = 79+ 1.5 \times (79 - 68)$

$U = 95.5$

This means that data below 51.5 or above 95.5 are outliers.

Hence, 99 is an outlier because 99 is greater than 95.5

(b) The parallel box plot

The three groups are:

Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99

Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82

Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0

3 years ago

Write a system of inequalities that defines a shaded region that looks like a right triangle.

eduard

$(1) \ x>0 \\ \\ (2) \ y>0 \\ \\ (3) \ y$

<h2>Explanation:</h2>

A right triangle is a special triangle that has a right angle. In this case, we have to write a system of inequalities that defines a shaded region that looks like a right triangle. First of all, let's say that at the origin the triangle will have a right angle. To do so, we'd need to set:

$x>0 \\ \\ y>0$

So the shaded region in this first part will be the First Quadrant as indicated in the first figure below. So if the opposite side lies on the x-axis the adjacent side will lie on the y-axis or if the adjacent side lies on the x-axis the opposite side will lie on the y-axis. Everything is ok up to this point. We just need to define the hypotenuse, so we'd need to define a line. In order to have a right triangle, we need a line with negative slope and positive y-intercept shaded under the line. So, this inequality could be:

$y$

Finally, the system of inequalities would be:

$(1) \ x>0 \\ \\ (2) \ y>0 \\ \\ (3) \ y$

And the final shaded region is the one shown in the second figure.

<h2>Learn more:</h2>

Inequalities: brainly.com/question/2486051

#LearnWithBrainly

3 0

3 years ago