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3 years ago

Find the GCF of 52 and 84.

Mathematics

1 answer:

Tema [17]3 years ago

5 0

Answer:

Step-by-step explanation:

The GCF of 52 and 84 is 4.

52 = 2 × 2 × 13

84 = 2 × 2 × 3 × 7

Therefore, GCF = 2 × 2

GCF = 4

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Sum divided by count. Add up all the numbers and divide it by how many numbers it is.

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3 years ago

camilla paid $1.15 per pound for x pounds of tomatoes. She paid for her tomatoes with $10 and received $4.48 in change. How many

Alika [10]

Answer:

$x=4.8\ pounds$

Step-by-step explanation:

Let

x-----> the number of pounds of tomatoes Camilla bought

we know that

The equation that represent this situation is equal to

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3 years ago

All eleven letters in the word GRASSHOPPER are put in a box. What is the probability of drawing a consonant from the box?

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2 years ago

IS the decimal number 5.078, the digit in the hundredths place is a 7.<br>TRUE OR FALSE?????

Ksju [112]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −

crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

$y = ax^2 + bx + c$

The solutions are:

$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$

In which:

$\Delta = b^2 - 4ac$

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

$\Delta = 150^2 - 4(-3)(-1200) = 8100$

$x_1 = \frac{-150 + \sqrt{8100}}{-6}$

$x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40$

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

$\Delta = 150^2 - 4(-3)(-1800) = 900$

$x_1 = \frac{-150 + \sqrt{900}}{-6}$

$x_2 = \frac{-150 - \sqrt{900}}{-6} = 30$

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0

2 years ago

Find the GCF of 52 and 84.​

Find the GCF of 52 and 84.