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monitta
3 years ago
6

Betty has 1/7 yard of ribbon. She used 1/6 of it. How many yards of ribbon did she use?

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

\frac{6}{7}

Step-by-step explanation:

SInce she used \frac{1}{6} of it we will divide \frac{1}{7} by \frac{1}{6}

\frac{1}{7}/ \frac{1}{6}=\frac{6}{7}


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How do you solve 9 tenths minus 13 fiftenths
Elena L [17]

Answer:

0.04

Step-by-step explanation:

1. 9/10 = 0.9 and 13/15 = 0.86

2. Subtract 0.9 and 0.86

3. You should end up with 0.04

Remember when a number goes like 0.86666666666 to use 0.86 or if it has 0.86666666667 to use 0.87 because you would be simplifying it.

4 0
3 years ago
Terry needs to carry a pole that
Natasha2012 [34]

Answer:

Yes, The pole will fit through the door because the diagonal width of the door is 10.8 feet, which is longer than the length of the pole.

Step-by-step explanation:

Using the Pythagorean Theorem, (a^2+b^2=c^2 ) we can measure the hypotenuse of a right triangle. Since the doorway is a rectangle, and a rectangle cut diagonally is a right triangle, we can use Pythagorean Theorem to measure the diagonal width of the doorway.

Plug in the values of the length and width of the door for a and b. The c value will represent the diagonal width of the doorway:

6^2+9^2=c^2

36+81=c^2

117=c^2

Since 117 is equal to the value of c multiplied by c, we must find the square root of 117 to find the value of c.

\sqrt{117} =10.8

10.8=c

Yes, The pole will fit through the door because the diagonal width of the door is 10.8 feet, which is longer than the length of the pole, measuring 10 feet.

7 0
3 years ago
ITS FOR A TEST PLS HELP
Artemon [7]
I think it’s 4 pairs cause 4 pants is less than 5 shoes and 8 is bigger than 4
8 0
3 years ago
Read 2 more answers
The width of a rectangle is x. Its length is 3x. How long is the diagonal of the rectangle? Express your answer in simplified ra
nikklg [1K]

Answer:

The length of the diagonal is x√10

Step-by-step explanation:

Here, we want to find the length of the diagonal

The diagonal will represent the hypotenuse of a triangle formed with the width and length of the triangle being the measure of the other sides

Mathematically, we then apply Pythagoras’ theorem to get this

we have this as that the square of the diagonal equals the sum of the squares of the two other sides

d^2 = x^2 + (3x)^2

d^2 = x^2 + 9x^2

d^2 = 10x^2

d = √(10x^2)

d = x√10

7 0
3 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
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