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1 year ago

Pierre throws a snowball up in the

Mathematics

1 answer:

erastovalidia [21]1 year ago

3 0

Using the given function, it is found that the snowball traveled 4 feet when the height is 20 feet.

<h3>What is the function for the ball's height?</h3>

The height when x feet are traveled is given by:

h(x) = -0.5x² + 6x + 4.

When the height is of 20 meters, we have that h(x) = 20, hence:

20 = -0.5x² + 6x + 4.

0.5x² - 6x + 16 = 0

x² - 12x + 32 = 0

(x - 8)(x - 4) = 0

For the first time: x - 4 = 0 -> x = 4.

The snowball traveled 4 feet when the height is 20 feet.

More can be learned about functions at brainly.com/question/25537936

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(-1,1)(0,4)(2,7)(3,7)

Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

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Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

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3 years ago

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2 years ago

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Answer:

Step-by-step explanation:

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2 years ago

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