Answer:
2.84*10^-3 years = 0.00284*10^-3 years
Explanation:
To find the orbital period you use the following formula:
r: 2.0A = 2.0(1.5*10^11m)=3*10^11 m
G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2
M: mass of the sun = 1.98*10^30 kg
Next, you calculate the time in seconds of one Earth's year:
thus, you use this value to find the orbital period of the asteroid in Earth's year:
Answer:
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It has an economy based on the production of goods and services demanded by the global economy.
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