Answer:
The distance can the water be projected is 4.51 m
Explanation:
The speed of the water in the hose is equal to:
v1 = R/A1
If we solve the continuity for v2:
v2 = R/A2 (eq. 1)
The equation for the vertical position is:
yf = yi + vy*t - (1/2)gt²
yi = 0
vy = 0
Clearing t:
(eq. 2)
The equation for position is:
xf = xi + vxt = 0 + v2t = v2t (eq. 3)
Replacing equation 1 and 2 in equation 3:
Answer:
Smallest collector size≈30
Explanation:
Daily sunlight intensity = 1400.
For a collector of 24% efficiency, the absorption per day per
= 0.24*1400 = 336.
For 8 hours, 25days of available sunlight, energy absorbed by collector per metre square , will be = 8* 25 *336 = 67200wh.
This is the amount of sunlight energy which will be trapped by 1. of collector in a month.
To find how many metre square of collector is required to get 2*kwh, we simply divide the required energy by the amount absorbed per square metre.
Smallest size of collected needed =
=29.76
≈30
Answer:
The answer is conductor
Explanation:
HOPE THIS ANSWER HELP YOU
Height increase h = R*(1 - cosΘ) = 1.2*(1-cos3.5°) = .00224 m.
<span>½Mbl*Vbl² = Mbl*g*h → </span>
<span>Vbl = √(2gh) = .2095 m/s </span>
<span>This is the initial velocity of the block. From momentum considerations, </span>
<span>Mbt*Vbt = Mbl*Vbl → </span>
<span>Vbt = (Mbl/Mbt)*Vbl = (5/.002)*.2095 = 523.8 m/s
this is what i think the answer is im not for sure though... hope it helps...</span>
Each element is made up of only one kind of atom.
Each element has their own atom.