A = L * L
400 = L²
√L² = √400
L = 20
The lenght of each side is 20
<u>Hello!</u> ✌.ʕʘ‿ʘʔ.✌
Okay, let's start by first combining like terms on the left side of the equal sign. (づ｡◕‿‿◕｡)づ
11x - 2x = 9x
Now we have 9x + 15 = 8 + 7 + 9x! <em><u>Wow! </u></em>(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
Now let's look at the right side.
8 + 7? That's easy! 15!
<u>So now we have...</u>
9x + 15 = 15 + 9x
Hmm... these equations are the same! So they will have infinite solutions! ᕙ(⇀‸↼‶)ᕗ
But let's keep going (￣。￣)～ｚｚｚ
<u>Subtract 15 from both sides:</u>
<u>9x + 15 (-15) = 15 (-15) + 9x</u>
9x = 9x
<u>Divide both sides by 9x:</u>
9x/9x = 9x/9x
0 = 0
So the answer is....
<u><em>Drum roll please!!!</em></u>
<u><em>Dun dun dun</em></u>
<u><em></em></u>
<u><em>Infinite solutions! Yay! Ｏ(≧▽≦)Ｏ</em></u>
<span><u>Answer</u>
25c^2-4/9
<u>Explanation</u>
In this question you are expected to expand (5c+2/3)(5c-2/3)
(5c+2/3)(5c-2/3)=(5c×5c)-(5c×2/3)+(5c×2/3)-(2/3×2/3)
=25c^2-10c/3+10c/3-4/9
25c^2-4/9
The expanded form of (5c+2/3)(5c-2/3) is 25c^2-4/9 and this is what the question requires of you to do.</span>
Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
