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andre [41]
3 years ago
8

Please HELP. 11x-2x+15=8+7+9x

Mathematics
1 answer:
ycow [4]3 years ago
6 0

<u>Hello!</u> ✌.ʕʘ‿ʘʔ.✌

Okay, let's start by first combining like terms on the left side of the equal sign. (づ。◕‿‿◕。)づ

11x - 2x = 9x

Now we have 9x + 15 = 8 + 7 + 9x! <em><u>Wow! </u></em>(ノ◕ヮ◕)ノ*:・゚✧

Now let's look at the right side.

8 + 7? That's easy! 15!

<u>So now we have...</u>

9x + 15 = 15 + 9x

Hmm... these equations are the same! So they will have infinite solutions! ᕙ(⇀‸↼‶)ᕗ

But let's keep going ( ̄。 ̄)~zzz

<u>Subtract 15 from both sides:</u>

<u>9x + 15 (-15) = 15 (-15) + 9x</u>

9x = 9x

<u>Divide both sides by 9x:</u>

9x/9x = 9x/9x

0 = 0

So the answer is....

<u><em>Drum roll please!!!</em></u>

<u><em>Dun dun dun</em></u>

<u><em></em></u>

<u><em>Infinite solutions! Yay! O(≧▽≦)O</em></u>

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Answer:

we need to prove : for every integer n>1, the number n^{5}-n is a multiple of 5.

1) check divisibility for n=1, f(1)=(1)^{5}-1=0  (divisible)

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3) Induction,

f(k+1)=(k+1)^{5}-(k+1)

=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1

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f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k

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f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)      (divisible by 5)

add both the sides by f(k)

f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)

We have proved that difference between f(k+1) and f(k) is divisible by 5.

so, our assumption in step 2 is correct.

Since f(k) is divisible by 5, then f(k+1) must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number n^{5}-n is a multiple of 5.

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2 years ago
A line with a slope of -4 has a coordinate of (0,3). If the other coordinate is (6,t),
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Answer:

Alrighty! So this is what we know:

Slope (m) = (-4)

Co-ordinate (0,3)

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Let's find our equation...

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3=0+b

b=3

We just found b! woohoo

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SO-

t=y

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SOOOOOOOO WE HAVE OUR T!! just write a therefore statement like "therefore the value of t is -21." and you're set! hope this helped, any questions? ask in the comment section. :)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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