rosa quilts a square rug that has an area of 400 square inches. what is the length of each side of the rug?

22 random samples were selected from a population that has a normal distribution the sample has a mean of 99 and a standard devi

olga2289 [7]

Answer:

(96.91, 101.09)

Step-by-step explanation:

To calculate the interval, you require the Z value at 95% confidence interval. The Z value is 1.96. The formula to calculate the confidence interval:

$X-Zs/\sqrt{x} \\X+Zs/\sqrt{x}$

Where X is the mean and s is the standard deviation and x the sample size:

$99-1.96\cdot{5}/\sqrt{22} \\99+1.96\cdot{5}/\sqrt{22}$

The interval is (96.91, 101.09)

3 0

3 years ago

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Please could someone help me ?

Juliette [100K]

Answer:

50% of 1/3: 1/2 x 1/3 = 1/6

75% of 1/2: 3/4 x 1/2 = 3/8

Step-by-step explanation:

50% = 1/2

50% of 1/3: 1/2 x 1/3 = 1/6

75% of 1/2: 3/4 x 1/2 = 3/8

6 0

3 years ago

seven less than the product of twice a number is greater than 5 more the same number which integer satisfies this inequality

JulsSmile [24]

To answer this question, we would have to use algebra.

Let the unknown number be A.

Now, as per the question, we have the equation ->
2A - 7 > 5 + A
==> 2A - A > 5+7
==> A > 12

So, the final answer is --> A > 12

4 0

3 years ago

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Evaluate 6y + x5<br> When x = -3, y = -5<br><br> please help <33 current failing:(

Radda [10]

Answer:

-35

Step-by-step explanation:

if you take 6 x -5 ( y ) then -3 x 5 ( x ) then add them together then you get -35.

8 0

3 years ago

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A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi

Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is $\mu \times n$ and the standard deviation is $\sigma\sqrt{n}$

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that $\mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300$

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20000 - 20000}{300}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

5 0

3 years ago