Answer:
2325
Step-by-step explanation:
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Answer:
Notice that the subjects of the study are men over 50 years.
So, you need to consider that each subject is a different person with different weight and other different characteristics that determine that weight.
If we have 10 groups randomly selected, that means there's gonna be variability, otherwise, the study wouldn't make sense.
So, if each person is different, then their weights is gonna be different, giving different means.
It would be rare if both means result equal, beacuse that would mean the subjects had the same weight.
Therefore, the variability between these means can be best attributed to the variability of subjects, the difference between each person.
From a numerical perspective, the variability is attributed to the spread of the data group, that is, if there is too much difference between weights, the variabilty will increase.
Given :
The Dobson exit is halfway between the Mt. Airy exit and the Elkin exit. If the Elkin exit is located at (-5,-2) and the Dobson exit is located at (-1,4).
To Find :
How far is it from the Elkin exit to the Mt. Airy exit.
Solution :
E(-5,-2) , D(-1 ,4 ) .
It is also given that Dobson exit is halfway between the Mt. Airy exit and the Elkin exit.
Let , location of Elkin exit is A(h,k) .
So , point D in terms of A and E is given by :
.
Comparing it with given D :
Therefore , the location of Mt. Airy exit is ( 3, 10 ) .
Distance between Elkin exit to the Mt. Airy exit.

Therefore , distance between Elkin exit to the Mt. Airy exit is 12.17 units .
Hence ,this is the required solution .